So, I learned this one when I was in my Calculus class and thought it was just sort of fun. Basically, there is a shape, called Gabriel's Horn (where you take the curve generated by the function f(x) = 1/x (where x >= 1)) and revolve it around the x-axis to form a horn shape.
Using calculus, you can calculate the volume of this shape (it doesn't show up very well, but π is PI:
Volume = π 1∫a (1/x2) dx = π (1 – 1/a)
So, lima->∞ π (1 – 1/a) = π (1 – 0) = π
The surface area can also be calculate as:
Surface Area = 2π 1∫a √(1 + 1/x4) / x dx
We know that √(1 + 1/x4) > √(1)...so we know that the Surface Area > 2π 1∫a √(1) / x dx = 2π ln a
So, lima->∞ 2π ln a = ∞
You might ask why this is a paradox...you can think of it this way:
Imagine you are a painter, it would take infinite amount of paint to paint the surface of this figure...however, you could FILL the entire shape with π volume of paint.
I like this one (I know WHY it isn't a paradox...but that's no fun to give that away right away...), so I thought I'd post it.
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Pickett
So, I learned this one when I was in my Calculus class and thought it was just sort of fun. Basically, there is a shape, called Gabriel's Horn (where you take the curve generated by the function f(x) = 1/x (where x >= 1)) and revolve it around the x-axis to form a horn shape.
Using calculus, you can calculate the volume of this shape (it doesn't show up very well, but π is PI:
Volume = π 1∫a (1/x2) dx = π (1 – 1/a)
So, lima->∞ π (1 – 1/a) = π (1 – 0) = π
The surface area can also be calculate as:
Surface Area = 2π 1∫a √(1 + 1/x4) / x dx
We know that √(1 + 1/x4) > √(1)...so we know that the Surface Area > 2π 1∫a √(1) / x dx = 2π ln a
So, lima->∞ 2π ln a = ∞
You might ask why this is a paradox...you can think of it this way:
Imagine you are a painter, it would take infinite amount of paint to paint the surface of this figure...however, you could FILL the entire shape with π volume of paint.
I like this one (I know WHY it isn't a paradox...but that's no fun to give that away right away...), so I thought I'd post it.
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