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Pandora's Box II.


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Pandora's Box II. - Back to the Logic Problems

And here is the second test. At least one inscription is true and at least one is false. Which means the ring is in the...

Golden box

The ring is not in the silver box.

Silver box

The ring is not in this box.

Lead box

The ring is in this box.

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Pandora's Box II. - solution

The ring must be in the golden box, otherwise all the inscriptions would be either true or false.

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  • 1 month later...

It is possible that it's in none of the boxes (I just mention this since I brought it up in Pandora's Box I).

-------------------------------------------------------------------------

|		 | Lead	   | Silver		 | Gold			| Total	   |

|		 | Ring here  | Ring not here  | Ring not silver | True/False  |

|---------+------------+----------------+-----------------+-------------|

| Gold	|	 F	  |	   T		|		T		|	 2/1	 |

|---------+------------+----------------+-----------------+-------------|

| Silver  |	 F	  |	   F		|		F		|	 0/3	 |

|---------+------------+----------------+-----------------+-------------|

| Lead	|	 T	  |	   T		|		T		|	 3/0	 |

|---------+------------+----------------+-----------------+-------------|

| None	|	 F	  |	   T		|		T		|	 1/2	 |

|-----------------------------------------------------------------------|

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  • 3 months later...
It is possible that it's in none of the boxes (I just mention this since I brought it up in Pandora's Box I).

Sure, if we want to think "outside the box," I could say it is in the lead box(T), which is inside the silver box(F), which is inside the gold box(F), but that would be silly. The original instructions said:

Based upon the inscriptions on the boxes (none or just one of them is true), choose one box where the wedding ring is hidden.
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  • 3 weeks later...

It is Possible that the ring is in none of these boxes but if it is any of the boxes then it is Golden Box.

Let us logically analyze each one of these inscriptions

Case one : Ring in the Lead Box

then ==> the Golden Box's inscription would be true ,

the silver Box's inscription would be true and so would that of the Lead Box.

However it is mentioned that 'at least one inscription is true and one is false ', so it cannot be the lead box as all the inscriptions turn out to be true.

Case two : Ring in the Silver Box

then == > the Golden Box's inscription would be false , the siver box's inscription false and the one for the Lead Box also be false.

Following the same logic as applied for the previous case as all the incsriptions can't be false , the ring is not in the Silver Box.

So the ring is in the Golden Box as in this case , the inscriptions on the Golden and Silver Box will be true and that of the Lead Box box will be false . This would be in cord with the condition that 'at least one inscription is true and one is false '

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  • 2 weeks later...

The inscriptions on Gold and Silver agree, so they must have the same truth value.

By conditions of the problem, Lead has the opposite truth value.

Gold and Silver False means

[1] Ring is in Silver

[2] Lead is true -> Ring is in Lead.

Contradiction

Gold and Silver True means

[1] Ring is in Gold or Lead

[2] Lead is false -> Ring is not in Lead.

Ring is in gold box.

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  • 4 months later...
  • 3 weeks later...

well if at least one of the incripts is lie and one is true.. so it can be one lie and two true.. or two lie and one true..

but it can only be one lie and two true.. Lead Box is telling a lie.. while the other two are telling the truth.. and u can judge that the ring is in the Golden Box..

Edited by Chakriya
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  • 2 weeks later...
  • 1 month later...

It's probably in the felt box...which actually meets all the preconditions and doesn't violate any of the wording of the problem or the choices for the solution since we were asked to choose one box, but never specifically one of the gold, silver, or lead boxes. ;-)

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