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## Question

If is possible to count from 0 to 100 using 4 4's for ever number

for example

0 = 4+4-4-4

1 = (4+4-4)/4

2 = (4 / 4) + (4 / 4)

3 = (4 * 4 - 4 ) / 4

4 = 4 * ( 4 - 4 ) + 4

5 = (4 * 4 + 4) / 4

6 =

7 =

8 =

9 =

10 =

.

.

.

.

.

100 =

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6 = (SQRT4) + 4 - 4 + 4

7 = (4/4) + (SQRT4) + 4

8 = 4 + 4 - 4 + 4

9 = 4/4 + 4 + 4

10 = (4*4) - 4 - (SQRT4)

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Because I almost play the piano, I'll grab this one:

44+44

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not sure if we can use stuff like 44 (or .4), but well,

0 = 4+4-4-4

1 = (4+4-4)/4

2 = (4 / 4) + (4 / 4)

3 = (4 * 4 - 4 ) / 4

4 = 4 * ( 4 - 4 ) + 4

5 = (4 * 4 + 4) / 4

6 = (4 + 4)/4 + 4

7 = 4 + 4 - 4/4

8 = (4 + 4) * 4/4

9 = 4 + 4 + 4/4

10 = (44 - 4)/4

12 = 4 * (4 - 4/4)

13 = 44/4 + sqrt(4)

14 = (4 - .4)*4 - .4

15 = 4*4 - 4/4

16 = 4 + 4 + 4 + 4

17 = 4*4 + 4/4

18 = (4.4)*4 + .4

20 = (4 + 4/4) * 4

21 = 4*4 + 4

22 = (44/4) * sqrt(4)

24 = 4*4 + 4 + 4

26 = 44/sqrt(4) + 4

28 = 4*(4+4) - 4

32 = 4*4 + 4*4

36 = 44 - 4 -4

43 = 44 - 4/4

44 = 44 + 4 - 4

45 = 44 + 4/4

48 = 4*(4+4+4)

52 = 44 + 4 + 4

60 = (4^4)/4 - 4

63 = (4^4 - 4)/4

64 = 4^(4 - 4/4)

65 = (4^4 + 4)/4

68 = (4^4)/4 + 4

80 = (44-4)*sqrt(4)

81 = (4 - 4/4)^4

88 = 44 + 44

92 = 44*sqrt(4) +4

96 = (44+4)*sqrt(4)

That\'s a start, I guess.

Edited by hellmake
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Yo, spoilers.

*edit* Never mind. Thank you.

Edited by Izzy
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54 = 44 + 4/.4

100 = 4/.4 x 4/.4

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54 = 44 + 4/.4

100 = 4/.4 x 4/.4

11 = 4/.4 + 4/4

• 0

44 - 4/.4

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54 = 44 + 4/.4

100 = 4/.4 x 4/.4

were getting there, only 58 more number to find

11 19 23 25 27 29 30 31 33 34 35 37 38 39 40 41 42 46 47 49 50 51 53 55 56 57 58 59 61 62 66 67 69 70 71 72 73 74 75 76 77 78 79 82 83 84 85 86 87 89 90 91 93 94 95 97 98 99

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were getting there, only 58 more number to find

11 19 23 25 27 29 30 31 33 34 35 37 38 39 40 41 42 46 47 49 50 51 53 55 56 57 58 59 61 62 66 67 69 70 71 72 73 74 75 76 77 78 79 82 83 84 85 86 87 89 90 91 93 94 95 97 98 99

to clear comfusion

anything with 4 4's is acceptable

44+44=88

( 4 / .4 ) *( 4 / 0.4)=100

some more hints include

4 ! = 4 * 3 * 2 * 1 = 24

44=256

4√(x)= x1/4

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How could we forget the factorial !?!

11 = 4/.4 + 4/4

23 = 4/(.4*.4) - sqrt(4)

25 = sqrt(4)*sqrt(4)/(.4*.4)

27 = 4/(.4*.4) + sqrt(4)

29 = 4/(.4*.4) + 4

30 = 4*4*sqrt(4) - sqrt(4)

34 = 4*4*sqrt(4) + sqrt(4)

40 = (4+4)*sqrt(4)/.4

42 = 4! * sqrt(4) - 4 - sqrt(4)

46 = 4! * sqrt(4) - 4 + sqrt(4)

47 = 4! * sqrt(4) - 4/4

49 = (sqrt(4)/.4 + sqrt(4))^sqrt(4)

50 = 4*sqrt(4)/(.4*.4)

55 = 44/(.4*sqrt(4))

56 = 4! * sqrt(4) + 4 + 4

72 = 4! + 44 + 4

leaves

19 31 33 35 37 38 39 41 51 53 57 58 59 61 62 66 67 69 70 71 73 74 75 76 77 78 79 82 83 84 85 86 87 89 90 91 93 94 95 97 98 99

Edited by hellmake
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72 = 4! * (4- (4/4))

11= (4/0.4) + (4/4)

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19 = 4! - 4 - 4/4

38 = (4*4)/.4 - sqrt(4)

58 = (4! + 4)* sqrt(4) +sqrt(4)

62 = (4^4)/4 - √4

66 = (4^4)/4 + √4

90 = 4! * 4 - 4 - sqrt(4)

91 = 4! * 4 - sqrt(4)/.4

94 = 4! * 4 - 4 + sqrt(4)

95 = 4! * 4 - 4/4

97 = 4! * 4 + 4/4

98 = 4! * 4 + 4 - sqrt(4)

leaves

31 33 35 37 39 41 51 53 57 59 61 67 69 70 71 73 74 75 76 77 78 79 82 83 84 85 86 87 89 93 99

Edited by hellmake
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31= 4! * sqrt4 - (4/4)

33= 4! *sqrt4 + (4/4)

Leaves 35 37 39 41 51 53 57 59 61 67 69 70 71 73 74 75 76 77 78 79 82 83 84 85 86 87 89 93 99

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100: (sqrt(4)+sqrt(4))*(4!)+4

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I'm an idiot, I thought 4! was 16 for some reason (I wasn't thinking I guess). Please ignore my last post and don't judge me for being temporarily stupid. <_<

So we still have

31 33 35 37 39 41 51 53 57 59 61 67 69 70 71 73 74 75 76 77 78 79 82 83 84 85 86 87 89 93 99

• 0

35 = (44/4) + 4!

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31 = 4! + sqrt(4)/.4 + sqrt(4)

33 = 4! + sqrt(4)/.4 + 4

59 = 4!/.4 - 4/4

61 = 4!/.4 + 4/4

70 = 4!/.4 + 4/.4

76 = (sqrt(4)/.4)! - 44

37 39 41 51 53 57 67 69 71 73 74 75 77 78 79 82 83 84 85 86 87 89 93 99

to go. We're getting there.

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51 = (4!-sqrt(4))/.4 - 4

53 = (4!-sqrt(4))/.4 - sqrt(4)

57 = (4!-sqrt(4))/.4 + sqrt(4)

67 = (4!+sqrt(4))/.4 + sqrt(4)

69 = (4!+sqrt(4))/.4 + 4

74 = (4!+4)/.4 + 4

75 = (4!+sqrt(4)+4)/.4

82 = (4!-4)*4 + sqrt(4)

84 = 44*sqrt(4) - 4

86 = 44*sqrt(4) - sqrt(4)

89 = (4!+sqrt(4))/.4 + 4!

37 39 41 71 73 77 78 79 83 85 87 93 99

left... starting to get difficult.

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I got one!

((4*4)+.4)/.4

37 39 71 73 77 78 79 83 85 87 93 99

left

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is using .04 allowed? or does that count as using a 0 and a 4?

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I got one!

((4*4)+.4)/.4

37 39 71 73 77 78 79 83 85 87 93 99

left

That would mean that:

((4*4)-.4)/4

37 71 73 77 78 79 83 85 87 93 99

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37 = 4!+(4!+sqrt4)/sqrt4

71 = (4! + 4.4)/.4

78 = 4*(4! - 4) - sqrt4

79 = 4! + (4! - sqrt4)/.4

83 = (4! - .4)/.4 + 4!

85 = (4! + 4/.4)/.4

73 77 87 93 99

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Why can't we use other powers other than -2?

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Why can't we use other powers other than -2?

i don't quite understand your question, but you are alound to use any combination of 4's and mathematical operators so perhaps -(sqrt(4))= -2?

Just for fun, here is the total list up to this point.

0 = 4+4-4-4

1 = (4+4-4)/4

2 = (4 / 4) + (4 / 4)

3 = (4 * 4 - 4 ) / 4

4 = 4 * ( 4 - 4 ) + 4

5 = (4 * 4 + 4) / 4

6 = (4 + 4)/4 + 4

7 = 4 + 4 - 4/4

8 = (4 + 4) * 4/4

9 = 4 + 4 + 4/4

10 = (44 - 4)/4

11 = 4/.4 + 4/4

12 = 4 * (4 - 4/4)

13 = 44/4 + sqrt(4)

14 = (4 - .4)*4 - .4

15 = 4*4 - 4/4

16 = 4 + 4 + 4 + 4

17 = 4*4 + 4/4

18 = (4.4)*4 + .4

19 = 4! - 4 - 4/4

20 = (4 + 4/4) * 4

21 = 4*4 + 4

22 = (44/4) * sqrt(4)

23 = 4/(.4*.4) - sqrt(4)

24 = 4*4 + 4 + 4

25 = sqrt(4)*sqrt(4)/(.4*.4)

26 = 44/sqrt(4) + 4

27 = 4/(.4*.4) + sqrt(4)

28 = 4*(4+4) - 4

29 = 4/(.4*.4) + 4

30 = 4*4*sqrt(4) - sqrt(4)

31 = 4! + sqrt(4)/.4 + sqrt(4)

32 = 4*4 + 4*4

33 = 4! + sqrt(4)/.4 + 4

34 = 4*4*sqrt(4) + sqrt(4)

35 = (44/4) + 4!

36 = 44 - 4 -4

37 = 4!+(4!+sqrt4)/sqrt4

38 = (4*4)/.4 - sqrt(4)

39=((4*4)-0.4)/0.4

40 = (4+4)*sqrt(4)/.4

41=((4*4)+0.4)/0.4

42 = 4! * sqrt(4) - 4 - sqrt(4)

43 = 44 - 4/4

44 = 44 + 4 - 4

45 = 44 + 4/4

46 = 4! * sqrt(4) - 4 + sqrt(4)

47 = 4! * sqrt(4) - 4/4

48 = 4*(4+4+4)

49 = (sqrt(4)/.4 + sqrt(4))^sqrt(4)

50 = 4*sqrt(4)/(.4*.4)

51 = (4!-sqrt(4))/.4 - 4

52 = 44 + 4 + 4

53 = (4!-sqrt(4))/.4 - sqrt(4)

54 = 44 + 4/.4

55 = 44/(.4*sqrt(4))

56 = 4! * sqrt(4) + 4 + 4

57 = (4!-sqrt(4))/.4 + sqrt(4)

58 = (4! + 4)* sqrt(4) +sqrt(4)

59 = 4!/.4 - 4/4

60 = (4^4)/4 - 4

61 = 4!/.4 + 4/4

62 = (4^4)/4 - √4

63 = (4^4 - 4)/4

64 = 4^(4 - 4/4)

65 = (4^4 + 4)/4

66 = (4^4)/4 + √4

67 = (4!+sqrt(4))/.4 + sqrt(4)

68 = (4^4)/4 + 4

69 = (4!+sqrt(4))/.4 + 4

70 = 4!/.4 + 4/.4

71 = (4! + 4.4)/.4

72 = 4! * (4- (4/4))

73=

74 = (4!+4)/.4 + 4

75 = (4!+sqrt(4)+4)/.4

76 = (sqrt(4)/.4)! - 44

77=

78 = 4*(4! - 4) - sqrt4

79 = 4! + (4! - sqrt4)/.4

80 = (44-4)*sqrt(4)

81 = (4 - 4/4)^4

82 = (4!-4)*4 + sqrt(4)

83 = (4! - .4)/.4 + 4!

84 = 44*sqrt(4) - 4

85 = (4! + 4/.4)/.4

86 = 44*sqrt(4) - sqrt(4)

87=

88 = 44 + 44

89 = (4!+sqrt(4))/.4 + 4!

90 = 4! * 4 - 4 - sqrt(4)

91 = 4! * 4 - sqrt(4)/.4

92 = 44*sqrt(4) +4

93=

94 = 4! * 4 - 4 + sqrt(4)

95 = 4! * 4 - 4/4

96 = (44+4)*sqrt(4)

97 = 4! * 4 + 4/4

98 = 4! * 4 + 4 - sqrt(4)

99=

100 = 4/.4 x 4/.4

keep up the good work!!

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Only 5 number left to find;

Can you find

73 77 87 93 99

using any combination of four 4's

these are the hard one but we've gone to far to give up now

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