Guest Posted February 4, 2009 Report Share Posted February 4, 2009 If is possible to count from 0 to 100 using 4 4's for ever number for example 0 = 4+4-4-4 1 = (4+4-4)/4 2 = (4 / 4) + (4 / 4) 3 = (4 * 4 - 4 ) / 4 4 = 4 * ( 4 - 4 ) + 4 5 = (4 * 4 + 4) / 4 6 = 7 = 8 = 9 = 10 = . . . . . 100 = Quote Link to post Share on other sites

0 Izzy 1 Posted February 4, 2009 Report Share Posted February 4, 2009 6 = (SQRT4) + 4 - 4 + 4 7 = (4/4) + (SQRT4) + 4 8 = 4 + 4 - 4 + 4 9 = 4/4 + 4 + 4 10 = (4*4) - 4 - (SQRT4) Quote Link to post Share on other sites

0 bonanova 85 Posted February 4, 2009 Report Share Posted February 4, 2009 Because I almost play the piano, I'll grab this one:44+44 Quote Link to post Share on other sites

0 Guest Posted February 4, 2009 Report Share Posted February 4, 2009 (edited) not sure if we can use stuff like 44 (or .4), but well, 0 = 4+4-4-4 1 = (4+4-4)/4 2 = (4 / 4) + (4 / 4) 3 = (4 * 4 - 4 ) / 4 4 = 4 * ( 4 - 4 ) + 4 5 = (4 * 4 + 4) / 4 6 = (4 + 4)/4 + 4 7 = 4 + 4 - 4/4 8 = (4 + 4) * 4/4 9 = 4 + 4 + 4/4 10 = (44 - 4)/4 12 = 4 * (4 - 4/4) 13 = 44/4 + sqrt(4) 14 = (4 - .4)*4 - .4 15 = 4*4 - 4/4 16 = 4 + 4 + 4 + 4 17 = 4*4 + 4/4 18 = (4.4)*4 + .4 20 = (4 + 4/4) * 4 21 = 4*4 + 4 22 = (44/4) * sqrt(4) 24 = 4*4 + 4 + 4 26 = 44/sqrt(4) + 4 28 = 4*(4+4) - 4 32 = 4*4 + 4*4 36 = 44 - 4 -4 43 = 44 - 4/4 44 = 44 + 4 - 4 45 = 44 + 4/4 48 = 4*(4+4+4) 52 = 44 + 4 + 4 60 = (4^4)/4 - 4 63 = (4^4 - 4)/4 64 = 4^(4 - 4/4) 65 = (4^4 + 4)/4 68 = (4^4)/4 + 4 80 = (44-4)*sqrt(4) 81 = (4 - 4/4)^4 88 = 44 + 44 92 = 44*sqrt(4) +4 96 = (44+4)*sqrt(4) That\'s a start, I guess. Edited February 4, 2009 by hellmake Quote Link to post Share on other sites

0 Izzy 1 Posted February 4, 2009 Report Share Posted February 4, 2009 (edited) Yo, spoilers. *edit* Never mind. Thank you. Edited February 4, 2009 by Izzy Quote Link to post Share on other sites

0 Prof. Templeton 10 Posted February 4, 2009 Report Share Posted February 4, 2009 54 = 44 + 4/.4 100 = 4/.4 x 4/.4 Quote Link to post Share on other sites

0 Guest Posted February 4, 2009 Report Share Posted February 4, 2009 54 = 44 + 4/.4 100 = 4/.4 x 4/.4 11 = 4/.4 + 4/4 Quote Link to post Share on other sites

0 bonanova 85 Posted February 4, 2009 Report Share Posted February 4, 2009 44 - 4/.4 Quote Link to post Share on other sites

0 Guest Posted February 4, 2009 Report Share Posted February 4, 2009 54 = 44 + 4/.4 100 = 4/.4 x 4/.4 were getting there, only 58 more number to find 11 19 23 25 27 29 30 31 33 34 35 37 38 39 40 41 42 46 47 49 50 51 53 55 56 57 58 59 61 62 66 67 69 70 71 72 73 74 75 76 77 78 79 82 83 84 85 86 87 89 90 91 93 94 95 97 98 99 Quote Link to post Share on other sites

0 Guest Posted February 4, 2009 Report Share Posted February 4, 2009 were getting there, only 58 more number to find 11 19 23 25 27 29 30 31 33 34 35 37 38 39 40 41 42 46 47 49 50 51 53 55 56 57 58 59 61 62 66 67 69 70 71 72 73 74 75 76 77 78 79 82 83 84 85 86 87 89 90 91 93 94 95 97 98 99 to clear comfusion anything with 4 4's is acceptable 44+44=88 ( 4 / .4 ) *( 4 / 0.4)=100 some more hints include 4 ! = 4 * 3 * 2 * 1 = 24 4^{4}=256 ^{4}√(x)= x^{1/4} Quote Link to post Share on other sites

0 Guest Posted February 4, 2009 Report Share Posted February 4, 2009 (edited) How could we forget the factorial !?! 11 = 4/.4 + 4/4 23 = 4/(.4*.4) - sqrt(4) 25 = sqrt(4)*sqrt(4)/(.4*.4) 27 = 4/(.4*.4) + sqrt(4) 29 = 4/(.4*.4) + 4 30 = 4*4*sqrt(4) - sqrt(4) 34 = 4*4*sqrt(4) + sqrt(4) 40 = (4+4)*sqrt(4)/.4 42 = 4! * sqrt(4) - 4 - sqrt(4) 46 = 4! * sqrt(4) - 4 + sqrt(4) 47 = 4! * sqrt(4) - 4/4 49 = (sqrt(4)/.4 + sqrt(4))^sqrt(4) 50 = 4*sqrt(4)/(.4*.4) 55 = 44/(.4*sqrt(4)) 56 = 4! * sqrt(4) + 4 + 4 72 = 4! + 44 + 4 leaves 19 31 33 35 37 38 39 41 51 53 57 58 59 61 62 66 67 69 70 71 73 74 75 76 77 78 79 82 83 84 85 86 87 89 90 91 93 94 95 97 98 99 Edited February 4, 2009 by hellmake Quote Link to post Share on other sites

0 Guest Posted February 4, 2009 Report Share Posted February 4, 2009 72 = 4! * (4- (4/4)) 11= (4/0.4) + (4/4) Quote Link to post Share on other sites

0 Guest Posted February 4, 2009 Report Share Posted February 4, 2009 (edited) 19 = 4! - 4 - 4/4 38 = (4*4)/.4 - sqrt(4) 58 = (4! + 4)* sqrt(4) +sqrt(4) 62 = (4^4)/4 - √4 66 = (4^4)/4 + √4 90 = 4! * 4 - 4 - sqrt(4) 91 = 4! * 4 - sqrt(4)/.4 94 = 4! * 4 - 4 + sqrt(4) 95 = 4! * 4 - 4/4 97 = 4! * 4 + 4/4 98 = 4! * 4 + 4 - sqrt(4) leaves 31 33 35 37 39 41 51 53 57 59 61 67 69 70 71 73 74 75 76 77 78 79 82 83 84 85 86 87 89 93 99 Edited February 4, 2009 by hellmake Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 31= 4! * sqrt4 - (4/4) 33= 4! *sqrt4 + (4/4) Leaves 35 37 39 41 51 53 57 59 61 67 69 70 71 73 74 75 76 77 78 79 82 83 84 85 86 87 89 93 99 Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 100: (sqrt(4)+sqrt(4))*(4!)+4 Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 I'm an idiot, I thought 4! was 16 for some reason (I wasn't thinking I guess). Please ignore my last post and don't judge me for being temporarily stupid. <_< So we still have 31 33 35 37 39 41 51 53 57 59 61 67 69 70 71 73 74 75 76 77 78 79 82 83 84 85 86 87 89 93 99 Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 35 = (44/4) + 4! Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 31 = 4! + sqrt(4)/.4 + sqrt(4) 33 = 4! + sqrt(4)/.4 + 4 59 = 4!/.4 - 4/4 61 = 4!/.4 + 4/4 70 = 4!/.4 + 4/.4 76 = (sqrt(4)/.4)! - 44 37 39 41 51 53 57 67 69 71 73 74 75 77 78 79 82 83 84 85 86 87 89 93 99 to go. We're getting there. Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 51 = (4!-sqrt(4))/.4 - 4 53 = (4!-sqrt(4))/.4 - sqrt(4) 57 = (4!-sqrt(4))/.4 + sqrt(4) 67 = (4!+sqrt(4))/.4 + sqrt(4) 69 = (4!+sqrt(4))/.4 + 4 74 = (4!+4)/.4 + 4 75 = (4!+sqrt(4)+4)/.4 82 = (4!-4)*4 + sqrt(4) 84 = 44*sqrt(4) - 4 86 = 44*sqrt(4) - sqrt(4) 89 = (4!+sqrt(4))/.4 + 4! 37 39 41 71 73 77 78 79 83 85 87 93 99 left... starting to get difficult. Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 I got one! ((4*4)+.4)/.4 37 39 71 73 77 78 79 83 85 87 93 99 left Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 is using .04 allowed? or does that count as using a 0 and a 4? Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 I got one! ((4*4)+.4)/.4 37 39 71 73 77 78 79 83 85 87 93 99 left That would mean that: ((4*4)-.4)/4 37 71 73 77 78 79 83 85 87 93 99 Quote Link to post Share on other sites

0 Prof. Templeton 10 Posted February 5, 2009 Report Share Posted February 5, 2009 37 = 4!+(4!+sqrt4)/sqrt4 71 = (4! + 4.4)/.4 78 = 4*(4! - 4) - sqrt4 79 = 4! + (4! - sqrt4)/.4 83 = (4! - .4)/.4 + 4! 85 = (4! + 4/.4)/.4 73 77 87 93 99 Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 Why can't we use other powers other than -2? Quote Link to post Share on other sites

0 Guest Posted February 5, 2009 Report Share Posted February 5, 2009 Why can't we use other powers other than -2? i don't quite understand your question, but you are alound to use any combination of 4's and mathematical operators so perhaps -(sqrt(4))= -2? Just for fun, here is the total list up to this point. 0 = 4+4-4-4 1 = (4+4-4)/4 2 = (4 / 4) + (4 / 4) 3 = (4 * 4 - 4 ) / 4 4 = 4 * ( 4 - 4 ) + 4 5 = (4 * 4 + 4) / 4 6 = (4 + 4)/4 + 4 7 = 4 + 4 - 4/4 8 = (4 + 4) * 4/4 9 = 4 + 4 + 4/4 10 = (44 - 4)/4 11 = 4/.4 + 4/4 12 = 4 * (4 - 4/4) 13 = 44/4 + sqrt(4) 14 = (4 - .4)*4 - .4 15 = 4*4 - 4/4 16 = 4 + 4 + 4 + 4 17 = 4*4 + 4/4 18 = (4.4)*4 + .4 19 = 4! - 4 - 4/4 20 = (4 + 4/4) * 4 21 = 4*4 + 4 22 = (44/4) * sqrt(4) 23 = 4/(.4*.4) - sqrt(4) 24 = 4*4 + 4 + 4 25 = sqrt(4)*sqrt(4)/(.4*.4) 26 = 44/sqrt(4) + 4 27 = 4/(.4*.4) + sqrt(4) 28 = 4*(4+4) - 4 29 = 4/(.4*.4) + 4 30 = 4*4*sqrt(4) - sqrt(4) 31 = 4! + sqrt(4)/.4 + sqrt(4) 32 = 4*4 + 4*4 33 = 4! + sqrt(4)/.4 + 4 34 = 4*4*sqrt(4) + sqrt(4) 35 = (44/4) + 4! 36 = 44 - 4 -4 37 = 4!+(4!+sqrt4)/sqrt4 38 = (4*4)/.4 - sqrt(4) 39=((4*4)-0.4)/0.4 40 = (4+4)*sqrt(4)/.4 41=((4*4)+0.4)/0.4 42 = 4! * sqrt(4) - 4 - sqrt(4) 43 = 44 - 4/4 44 = 44 + 4 - 4 45 = 44 + 4/4 46 = 4! * sqrt(4) - 4 + sqrt(4) 47 = 4! * sqrt(4) - 4/4 48 = 4*(4+4+4) 49 = (sqrt(4)/.4 + sqrt(4))^sqrt(4) 50 = 4*sqrt(4)/(.4*.4) 51 = (4!-sqrt(4))/.4 - 4 52 = 44 + 4 + 4 53 = (4!-sqrt(4))/.4 - sqrt(4) 54 = 44 + 4/.4 55 = 44/(.4*sqrt(4)) 56 = 4! * sqrt(4) + 4 + 4 57 = (4!-sqrt(4))/.4 + sqrt(4) 58 = (4! + 4)* sqrt(4) +sqrt(4) 59 = 4!/.4 - 4/4 60 = (4^4)/4 - 4 61 = 4!/.4 + 4/4 62 = (4^4)/4 - √4 63 = (4^4 - 4)/4 64 = 4^(4 - 4/4) 65 = (4^4 + 4)/4 66 = (4^4)/4 + √4 67 = (4!+sqrt(4))/.4 + sqrt(4) 68 = (4^4)/4 + 4 69 = (4!+sqrt(4))/.4 + 4 70 = 4!/.4 + 4/.4 71 = (4! + 4.4)/.4 72 = 4! * (4- (4/4)) 73= 74 = (4!+4)/.4 + 4 75 = (4!+sqrt(4)+4)/.4 76 = (sqrt(4)/.4)! - 44 77= 78 = 4*(4! - 4) - sqrt4 79 = 4! + (4! - sqrt4)/.4 80 = (44-4)*sqrt(4) 81 = (4 - 4/4)^4 82 = (4!-4)*4 + sqrt(4) 83 = (4! - .4)/.4 + 4! 84 = 44*sqrt(4) - 4 85 = (4! + 4/.4)/.4 86 = 44*sqrt(4) - sqrt(4) 87= 88 = 44 + 44 89 = (4!+sqrt(4))/.4 + 4! 90 = 4! * 4 - 4 - sqrt(4) 91 = 4! * 4 - sqrt(4)/.4 92 = 44*sqrt(4) +4 93= 94 = 4! * 4 - 4 + sqrt(4) 95 = 4! * 4 - 4/4 96 = (44+4)*sqrt(4) 97 = 4! * 4 + 4/4 98 = 4! * 4 + 4 - sqrt(4) 99= 100 = 4/.4 x 4/.4 keep up the good work!! Quote Link to post Share on other sites

0 Guest Posted February 6, 2009 Report Share Posted February 6, 2009 Only 5 number left to find; Can you find 73 77 87 93 99 using any combination of four 4's these are the hard one but we've gone to far to give up now Quote Link to post Share on other sites

## Question

## Guest

If is possible to count from 0 to 100 using 4 4's for ever number

for example

0 = 4+4-4-4

1 = (4+4-4)/4

2 = (4 / 4) + (4 / 4)

3 = (4 * 4 - 4 ) / 4

4 = 4 * ( 4 - 4 ) + 4

5 = (4 * 4 + 4) / 4

6 =

7 =

8 =

9 =

10 =

.

.

.

.

.

100 =

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