Jump to content
BrainDen.com - Brain Teasers
  • 0


Guest

Question

4 answers to this question

Recommended Posts

  • 0
In the park one day, I saw a great assortment of children and dogs. Counting heads, I saw 22. Counting legs, I saw 68.

How many children and dogs were in the park?

c = children, d = dogs

c+d = 22

2c+4d = 68

subtract the first from the second:

(2c+4d)-(c+d) = 68-22

c+3d = 46

subtract the first from this

(c+3d)-(c+d) = 46-22

2d = 24

d = 12

which means c has to be 22-12 = 10

10 children, 12 dogs

checking: 20 legs + 48 legs = 68 legs

~~~

alternatively, you could do it this way:

c+d = 22

2c+4d = 68

divide the second equation by 2

c+d = 22

c+2d = 34

subtract the first from the second, and you get d = 12, and it follows that c = 10

Link to post
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Answer this question...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
  • Recently Browsing   0 members

    No registered users viewing this page.

×
×
  • Create New...