itachi-san Posted May 27, 2008 Report Share Posted May 27, 2008 What kind of poem am I? (12 + 144 + 20 + (3 x (4^.5)))/7 + 5 x 11 = (9 ^2) + 0 a limerick A dozen a gross and a score, Plus three times the square root of four, Divided by seven, Plus five times eleven, Is nine squared and not a bit more Quote Link to comment Share on other sites More sharing options...

0 Guest Posted May 27, 2008 Report Share Posted May 27, 2008 I like it! Here's another one I found... 4 + (6! - 0.5(12^2 + (403 + 1))) = 2(15^2) Four plus the difference between The factorial of six and the mean Of twelve squared and four Hundred three (plus one more) Equals double the square of fifteen. Quote Link to comment Share on other sites More sharing options...

0 Guest Posted May 27, 2008 Report Share Posted May 27, 2008 And I haven't personally checked this but I'll take it on faith... The integral of z-squared dz, From 1 to the cube root of 3, Times the cosine, Of 3 pi by 9, Is the log of the cube root of e. Quote Link to comment Share on other sites More sharing options...

0 Guest Posted February 8, 2010 Report Share Posted February 8, 2010 I wrote the second limerick in 2005. I had read the first one (the "a dozen a gross, and a score" one) which was written by the late John Saxon and was inspired to write my own. I was in the middle of a 4th grade teacher inservice meeting, but, in between round table discussions, I worked on finding a way to get the numbers just right so that the limerick would contain a true equation. It took about an hour. I knew I wanted mean average, a square, and a factorial in the limerick, and I knew that the first, second, and fifth lines would contain the words "between", "mean", and something-"teen", so I worked around that. Now, I have something really cool to show my students each year. Quote Link to comment Share on other sites More sharing options...

0 unreality Posted February 8, 2010 Report Share Posted February 8, 2010 And I haven't personally checked this but I'll take it on faith... <div style="margin:20px; margin-top:5px"> <div class="smallfont" style="margin-bottom:2px">Spoiler for answer: <input type="button" value="Show" style="width:45px;font-size:10px;margin:0px;padding:0px;" onClick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = ''; this.innerText = ''; this.value = 'Hide'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'Show'; }"> </div><div class="alt2" style="margin: 0px; padding: 6px; border: 1px inset;"><div style="display: none;">The integral of z-squared dz, From 1 to the cube root of 3, Times the cosine, Of 3 pi by 9, Is the log of the cube root of e. </div></div></div> the integral of z^2 dz = z^3 / 3, from 1 to cube root of 3 is: (cubrt3)^3 / 3 - 1^3 / 3 3/3 - 1/3 2/3 2/3 times the cosine of 3pi/9 = 2/3 * cos(pi/3) = 2/3 * 1/2 = 1/3 so the left side evaluates to 1/3 the right side is ln(e^1/3), so pull out the power: 1/3 * ln(e) = 1/3 * 1 = 1/3 so both sides are 1/3 Quote Link to comment Share on other sites More sharing options...

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## itachi-san

What kind of poem am I?

(12 + 144 + 20 + (3 x (4^.5)))/7 + 5 x 11 = (9 ^2) + 0

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