Guest Posted May 14, 2008 Report Share Posted May 14, 2008 This is one of my favourite puzzles: (1/n)*sinx = 6 All you have to do is prove this statement is true. Quote Link to comment Share on other sites More sharing options...
0 Nikyma Posted May 14, 2008 Report Share Posted May 14, 2008 six=6 Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted May 14, 2008 Report Share Posted May 14, 2008 six=6 Do NOT mess with this lady ... she is good. Quote Link to comment Share on other sites More sharing options...
0 Nikyma Posted May 14, 2008 Report Share Posted May 14, 2008 Do NOT mess with this lady ... she is good. You flatter me so. Quote Link to comment Share on other sites More sharing options...
0 akaslickster Posted May 14, 2008 Report Share Posted May 14, 2008 sinx is not a word but this is not difficult I'm sure. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 14, 2008 Report Share Posted May 14, 2008 Man You have TWO vars and one constant.. n and x could be anything. if we can assume it then let n be 1/6 and x should be 90 then 1/(1/6) * sin90 = 6, or let it be any other numbers that fulfill the equation Quote Link to comment Share on other sites More sharing options...
0 Nikyma Posted May 14, 2008 Report Share Posted May 14, 2008 Man You have TWO vars and one constant.. n and x could be anything. if we can assume it then let n be 1/6 and x should be 90 then 1/(1/6) * sin90 = 6, or let it be any other numbers that fulfill the equation the n's negate each other...leaving 1*six=6 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 14, 2008 Report Share Posted May 14, 2008 Congrats Nikyma Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 14, 2008 Report Share Posted May 14, 2008 Man You have TWO vars and one constant.. n and x could be anything. if we can assume it then let n be 1/6 and x should be 90 then 1/(1/6) * sin90 = 6, or let it be any other numbers that fulfill the equation They cannot be anything: First of all, n cannot be zero (otherwise you are in trouble. Why??). Second of all, if you multiply both equations by "n" you get Sin x = 6n. The later equation only has (real) solutions when |n| <=1/6 (Infinitely many as a matter of fact). Thus you must have (in order for the problem to be solved in a lets say "more standard" mathematical way) the constraint 0 < | n | <= 1/6 P.S. If you have | n | > 1/6 then you still have infinitely many (complex) solutions. Granted, this eliminates one part of the constraint but we still have the other: n cannot be zero Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 14, 2008 Report Share Posted May 14, 2008 six=6 I would never have thought of that. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 14, 2008 Report Share Posted May 14, 2008 They cannot be anything: First of all, n cannot be zero (otherwise you are in trouble. Why??). Second of all, if you multiply both equations by "n" you get Sin x = 6n. The later equation only has (real) solutions when |n| <=1/6 (Infinitely many as a matter of fact). Thus you must have (in order for the problem to be solved in a lets say "more standard" mathematical way) the constraint 0 < | n | <= 1/6 P.S. If you have | n | > 1/6 then you still have infinitely many (complex) solutions. Granted, this eliminates one part of the constraint but we still have the other: n cannot be zero After you have sin x=6n---divide each side by n leaving six=6 not real math but i think thats the point of the riddle Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 22, 2008 Report Share Posted May 22, 2008 Well I was thinking Mathematical way expecting sinx to be sinx and can't remove the n just like that ... but that's a good one and yomero7, I didn't say any numbers. I said the numbers for both n and x that fulfill the equation.. well see you all Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 22, 2008 Report Share Posted May 22, 2008 Good to see some people trying to prove this using real math if anyone comes up with a solution using real math it would be interesting to see. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 22, 2008 Report Share Posted May 22, 2008 lol, that maths problem is so simple but, it seemed so complex... Quote Link to comment Share on other sites More sharing options...
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Guest
This is one of my favourite puzzles:
(1/n)*sinx = 6
All you have to do is prove this statement is true.
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