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Sequence puzzle


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Go to solution Solved by rookie1ja,

Question

The below is a number puzzle. It should be read left to right, top to bottom.

Question 1 What is the next two rows of numbers.

Question 2 How was this reached.

1 1

2 1

1 2 1 1

1 1 1 2 2 1

? ? ? ? ? ?

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The below is a number puzzle. It should be read left to right, top to bottom.

Question 1 What is the next two rows of numbers.

Question 2 How was this reached.

1 1

2 1

1 2 1 1

1 1 1 2 2 1

? ? ? ? ? ?

3 1 2 2 1 1

1 3 1 1 2 2 2 1

this is a google placement question

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They just made a reverse of previous one.. that is if 2 1 means they wrote 1 2 then writing the previous one in reverse order.. thro that i made like the following.the sequence should be in the following order

1 1

2 1

1 2 1 1

1 1 1 2 2 1

so ans 1 2 2 1 1 1 1 2 1.... kiruba.d

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One small problem with the solution, you are no longer following the question of reading left to right. You are grouping. Thus if grouping is allowed, and it appears to be because that is the answer

1

11

21

1211

3112

132112

312213

and so on would be the solution

IF we stick with reading left to right it would become

1

11

21

1211

11121111

11111112111111

In other words you would be saying "one 1, one 2, one 1, one 1"

Based on the initial question, your answers are all wrong.

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One small problem with the solution, you are no longer following the question of reading left to right. You are grouping. Thus if grouping is allowed, and it appears to be because that is the answer

1

11

21

1211

3112

132112

312213

and so on would be the solution

IF we stick with reading left to right it would become

1

11

21

1211

11121111

11111112111111

In other words you would be saying "one 1, one 2, one 1, one 1"

Based on the initial question, your answers are all wrong.

Your solution does not follow the pattern of the original sequence. The solution posted in post #2 is the only possible. If we follow your reasoning the sequence would look like this...

1

11

1111

11111111

and so on.

Edited by Prof. Templeton
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