bonanova Posted March 21, 2018 Report Share Posted March 21, 2018 If you chose to answer this question completely at random, what is the probability you will be correct? 25% 50% 0% 25% Quote Link to comment Share on other sites More sharing options...

0 Pickett Posted March 21, 2018 Report Share Posted March 21, 2018 Haha, that's kind of fun to wrap your head around... Spoiler But really, it should be fairly simple, I think: Each option has a 25% chance of being randomly picked. That is the correct answer: 25%. BUT there are two options where "25%" is the answer. This means that the answer that you pick has a 50% chance of being "25%", which is STILL the correct answer regardless of the probability of picking an answer that HAS that value. So the probability that you are correct is 50% which is answer 2... Quote Link to comment Share on other sites More sharing options...

0 ThunderCloud Posted March 21, 2018 Report Share Posted March 21, 2018 This is a fun one... Spoiler I'd say the probability of randomly choosing the correct answer is 0%. If any of answers (1, 2, 3, and/or 4) is considered correct, it results in a contradiction. So, none of the answers may be considered correct (including option 3). Quote Link to comment Share on other sites More sharing options...

0 ThunderCloud Posted March 21, 2018 Report Share Posted March 21, 2018 42 minutes ago, ThunderCloud said: This is a fun one... Reveal hidden contents I'd say the probability of randomly choosing the correct answer is 0%. If any of answers (1, 2, 3, and/or 4) is considered correct, it results in a contradiction. So, none of the answers may be considered correct (including option 3). Then again... Spoiler It also seems contradictory to claim that the probability is 0% and yet answer choice #3 is not correct. So, perhaps the only consistent assessment is that the probability of guessing a correct answer is undefined. The question is, after all, a paradox. Quote Link to comment Share on other sites More sharing options...

0 Thalia Posted March 22, 2018 Report Share Posted March 22, 2018 15 hours ago, Pickett said: Haha, that's kind of fun to wrap your head around... Hide contents But really, it should be fairly simple, I think: Each option has a 25% chance of being randomly picked. That is the correct answer: 25%. BUT there are two options where "25%" is the answer. This means that the answer that you pick has a 50% chance of being "25%", which is STILL the correct answer regardless of the probability of picking an answer that HAS that value. So the probability that you are correct is 50% which is answer 2... So... The probability that you choose the correct value of 25% is 50% but since 50% is not 25%, you'd be part of the 50% that guessed wrong? Quote Link to comment Share on other sites More sharing options...

0 harey Posted March 22, 2018 Report Share Posted March 22, 2018 (edited) Spoiler By definition, p(to be correct at random)=(number of correct answers)/(number of answers) As the (number of correct answers) is not known, p cannot be calculated. Even if the possible answers were {15%, 25%, 35%, 45%}, the problem would remain meaningless. One could believe 25% to be the correct answer. Why should it be correct? Don't tell me It is correct because it is correct. Edited March 22, 2018 by harey Quote Link to comment Share on other sites More sharing options...

0 ThunderCloud Posted March 25, 2018 Report Share Posted March 25, 2018 A more detailed answer… Spoiler If the question is to be interpreted to suggest that one of (1), (2), (3), or (4) is the correct answer, and that one of those four answers is chosen randomly such that each has a 25% probability of selection, then it can be shown that the question has no answer: Among the answer choices given, there are three distinct probabilities: 50%, 25%, and 0%. If the correct answer is 50%, then since this is only one out of four answer choices, the probability must in fact be 25%. That is, by assuming the correct answer is 50%, we obtain that it is not 50%. Similarly, if we assume the correct answer is 25%, then since two out of four answer choices are correct, the real answer must be 50%… i.e., not 25%, a contradiction once again. If we assume that the answer is 0%, then answer (3) is correct and the probability of choosing it is 25%, not 0%, once again a contradiction. Finally, if we assume that the probability is anything else not listed as an answer choice, then the probability of choosing it is 0% (and therefore, 25%, etc…), meaning it is, in fact, listed among the answer choices. Once again, a contradiction. For any 0% ≤ p ≤ 100%, if we assume the correct answer is p, then we must conclude that it is not p. There cannot be a consistent answer. On the other hand, if the question is interpreted to suggest that it is answered as an entirely random probability (any real number between 0% and 100%, without regard to the listed answer choices), then the probability of choosing the precisely correct answer is 0%, as non-zero probabilities can only occur over an interval (e.g., probability of choosing the correct answer ± 1%). Quote Link to comment Share on other sites More sharing options...

## Question

## bonanova

If you chose to answer this question completely at random, what is the probability you will be correct?

## Link to comment

## Share on other sites

## 6 answers to this question

## Recommended Posts

## Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.