BMAD 63 Report post Posted March 8 let a = ln(ln(x))/(ln(x) let b= x^{a} let y = e^{b} find dy/dx Share this post Link to post Share on other sites

0 bonanova 79 Report post Posted Monday at 03:31 PM (edited) Looks like ... Spoiler dy/dx = 1 Spoiler b = x^{a} = e^{a ln x} = e^{ln ln x} = ln xy = e^{b} = e^{ln x} = x Edited Monday at 07:15 PM by bonanova Further simplification Share this post Link to post Share on other sites

0 bonanova 79 Report post Posted March 10 Spoiler Spoiler But seriously, working on it. Share this post Link to post Share on other sites

let a = ln(ln(x))/(ln(x)

let b= x

^{a}let y = e

^{b}find dy/dx

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