In a previous puzzle@plasmid found that by successively doubling the jelly beans on a plate by transferring from one of the other of three plates, it's possible to empty one of the plates.

Suppose the starting number of jelly beans distributed among three plates is a sufficiently nice multiple of 3, namely b = 3x2^{n}. By making successive doubling moves, as in the first puzzle, is it always possible to end up with an equal number ( 2^{n} ) of jelly beans on the three plates?

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## bonanova 85

In a previous puzzle @plasmid found that by successively doubling the jelly beans on a plate by transferring from one of the other of three plates, it's possible to empty one of the plates.

Suppose the starting number of jelly beans distributed among three plates is a sufficiently nice multiple of 3, namely

= 3x2b^{n}. By making successive doubling moves, as in the first puzzle, is it always possible to end up with an equal number ( 2^{n}) of jelly beans on the three plates?## Link to post

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