jasen Posted July 11, 2016 Report Share Posted July 11, 2016 arrange the digits from 0 to 9 into a number so the number is divisible by 12 to 21. (there are 2 answers) Quote Link to comment Share on other sites More sharing options...

1 DejMar Posted July 11, 2016 Report Share Posted July 11, 2016 (edited) Spoiler The prime factors of 12 to 21 are 2^{4}×3×5×7×13×17×19, therefore the two 10-digit pandigital numbers are a multiple of 7054320. These two numbers are 2137458960 [7054320×303] and 6179584320 [7054320×876]. It can be noted that as a multiple of 7054320, the final digit must be 0. Edited July 11, 2016 by DejMar Additional information Quote Link to comment Share on other sites More sharing options...

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## jasen

arrange the digits from 0 to 9 into a number so the number is divisible by 12 to 21.

(there are 2 answers)

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