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afhbg?

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13 hours ago, Mr.Dog said:

afhbg?

No..sorry...try again

Note that:  abcdef= 0

On 20.3.2016 at 9:10 PM, wolfgang said:

abcdef
bc
abged
abgcd
fgbc
.........?
afedcg
abc

Note that: abcdef= 0

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Alright, think i got it after fiddling with the unique number values for the letters.

Spoiler

Sol. abedcg = 5

( a=6 , b = -2 , c = 3 , d = -8 , e = 2, f = -1 , g = 4),

steps:

1. fedcg=abcdef            2. (fg)(bc)= (3)+(1)=4       3. (ab)cdef=0 ---> (g)cdef=0 ----> (gf)cde=0---> 3cde=0

g=ab

4. Trial and error with abged = 2 , abgcd = 3 and 3cde = 0, easier when you know that g=ab.

abcdef = 0
bc = 1
abged = 2
abgcd = 3
fgbc = 4
abedcg = 5
afedcg = 6
abc = 7

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On 25.3.2016 at 2:13 AM, Mr.Dog said:

Alright, think i got it after fiddling with the unique number values for the letters.

Hide contents

Sol. abedcg = 5

( a=6 , b = -2 , c = 3 , d = -8 , e = 2, f = -1 , g = 4),

steps:

1. fedcg=abcdef            2. (fg)(bc)= (3)+(1)=4       3. (ab)cdef=0 ---> (g)cdef=0 ----> (gf)cde=0---> 3cde=0

g=ab

4. Trial and error with abged = 2 , abgcd = 3 and 3cde = 0, easier when you know that g=ab.

abcdef = 0
bc = 1
abged = 2
abgcd = 3
fgbc = 4
abedcg = 5
afedcg = 6
abc = 7

Amasing!!! you did find all the sequences from 0 to 7 ...but  5 is wrong..

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how xD?

Spoiler

abedcg = 6 + (-2) + 2 + (-8) + 3 + 4 = 5

also:

abged=2

abgcd=3

change with 1 different letter,

so it kind of make sense that:

abedcg=5

afedcg=6

change with 1 letter.

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