BrainDen.com - Brain Teasers
• 0

# nazi numbers

Go to solution Solved by Thalia,

## Question

create a m x n table.
then put the multiplication result of x,y coordinate in each cell.

set any cell as your preffered base.
from the base go up    A steps, then go right (or left) B steps, take the number as num1
from the base go left  A steps, then go right (or left) B steps, take the number as num2
from the base go down  A steps, then go right (or left) B steps, take the number as num3
from the base go right A steps, then go right (or left) B steps, take the number as num4

(num1 + num2 + num3 + num4) / 4 = your number.

anybody can explain this ?

## Recommended Posts

• 0
• Solution
Spoiler

Don't forget combinations of Y,A and B,X.

The math:

[(x-b)(y-a) + (x-a)(y+b) + (x+b)(y+a) + (x+a)(y-b)]/4=xy

[xy-by-ax+ab+xy+bx-ay-ab+xy+ax+by+ab+xy-bx+ay-ab]/4=xy

[4xy]/4=xy

Edited by Thalia
##### Share on other sites
• 0

First of all you don't proofread your typing,if you go right or left A cells, go up or down B cells

Spoiler
Spoiler

your cell number is X*Y  each or the 4 numbers generated will be ( X+A ) ,or (X-A) ,times (Y+B), or (Y-B).  Add the 4 numbers and you get 4XY

##### Share on other sites
• 0
7 hours ago, jhawk said:

First of all you don't proofread your typing,if you go right or left A cells, go up or down B cells

Hide contents
Hide contents

your cell number is X*Y  each or the 4 numbers generated will be ( X+A ) ,or (X-A) ,times (Y+B), or (Y-B).  Add the 4 numbers and you get 4XY

sorry if my words is confusing.
I mean go right (or left) from last position.

If I draw from your answer, the shape will be a rectangular on a flat surface.
_______
|       |
|   x   |
|_______|

## Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

×   Pasted as rich text.   Paste as plain text instead

Only 75 emoji are allowed.

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.