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# Ratio of the two splitted fragments created by drawing a perpendicular projection from one vertex (i.e., one angle) of a triangle to its opossite side

## Question

In triangle ABC, Let D be the foot of the perpendicular drawn from B onto the opposite side AC. Then, is it that the ratio's AB / BC = AD / DC = <ABD/<DBC ?

I presume it is true. But, can one suggest an analytical proof of this theorem ? Or state otherwise the reason (if it is not true).

It would be of much help.

- Thanks and regards

Sankar Basu

Post Doc

Bioinformatics

## Recommended Posts

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Your presumption is wrong. Here is a counterexample:

AB/BC = 0.75

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