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Find the radius


Go to solution Solved by Rob_G,

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I no longer remember whether I ever knew this, but...

Since I haven't learned how to send you a picture,
Let's name some coordinates:
* m = left end of the diameter
* n = right end of the x-length segment on the diameter
* p = touching corner of the square
* q = right end of the diameter

and let's name some lengths:
* s = sqrt(A), 
* t = distance from n to q

I don't remember whether this is true, but
IF the angle formed by mpq is a right angle, then
triangle (mnp) is similar to triangle (npq)
and

x/s = s/t
t = s^2/x = A/x
radius = (x + A/x) / 2

So, I've caught up with Rob

Edited by CaptainEd
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