BMAD Posted June 21, 2014 Report Share Posted June 21, 2014 Here is a simple one: If two dice are rolled, the likelihood that the total on the two dice will be 5 is 1/9. Suppose two dice are rolled 50 times. Find the probability that exactly 6 rolls have a result of 5. Find the probability that 10 or fewer rolls have a result of 5. Quote Link to comment Share on other sites More sharing options...

0 m00li Posted June 22, 2014 Report Share Posted June 22, 2014 exactly 6 rolls have a result of 5 = ^{50}C_{6}(1/9)^{6}(8/9)^{44} 10 or fewer rolls have a result of 5 = S_{0->10}^{50}C_{k}(1/9)^{k}(8/9)^{50-k} , where S_{a}_{->b} denotes sum over a to b Quote Link to comment Share on other sites More sharing options...

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## BMAD

Here is a simple one:

If two dice are rolled, the likelihood that the total on the two dice will be 5 is 1/9. Suppose two dice are rolled 50 times.

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