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Find out a four digit integer which is a square of something and also the first 2 and last 2 digits combined are also the squares of something.

eg. ABCD is a square and AB & CD are also square of something.

Find this Integer

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Find out a four digit integer which is a square of something and also the first 2 and last 2 digits combined are also the squares of something.

eg. ABCD is a square and AB & CD are also square of something.

Find this Integer

1681

1681 = 41*41

16 = 4*4

81 = 9*9

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If I'm understanding the question correctly.

1681 = 41^2

16 = 4^2

81 = 9^2

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Posted · Report post

40*40=1600

eventhough 0 is not an integer. ;)

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If there is no rules on A must be not equal with B, B must be not equal with C and so on...

then the answer is

1681 = 41 x 41

as 16 = 4 x 4

and 81 = 9 x 9,

but however, A = D

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Posted · Report post

1681=412

where 16=42

and 81=92

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Posted · Report post

41^2=1681

16=4^2

81=9^2

Find out a four digit integer which is a square of something and also the first 2 and last 2 digits combined are also the squares of something.

eg. ABCD is a square and AB & CD are also square of something.

Find this Integer

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