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Guessing the right card

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A deck of 26 red and 26 black cards is shuffled into random order and placed face down. Then the cards are turned up one by one and observed by a guesser. He gets one guess: At a moment of his choice he may assert that the next card will turn up red. After this card is turned up the game ends and he wins if his assertion was correct, loses otherwise. And if he doesn't guess at all by the time all cards have been dealt, he loses by default.

He receives 2x(x-1) dollars for a correct guess but loses (n(n-1)) + 2x(x-1) dollars for an incorrect guess;

x is the number of cards faced down (unseen by the guesser) and n is the number of cards shown to the guesser.

How should the guesser play the game? Does the strategy change if they were to play the game 1000 times?

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Posted · Report post

It seems you want to maximize x.
I think a previous puzzle showed every strategy is equivalent to betting on the last card, which wins half the time.
So bet on the first card.

Clarify for 1000 times. Do you parlay your winnings?

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Posted · Report post

No you do not.

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