One million dollar coins are thrown into two urns in the following manner: At the beginning of the process, each urn contains one coin. The remaining 999,998 coins are thrown in one by one. Each coin lands into one of the two urns with different probabilities. If at any stage of the process the first urn contains x coins and the second urn contains y coins, then the probabilities that the thrown coin will fall into the first or second urn are:

x/(x+y) and y/(x+y)

The question is: how much should you pay (in advance) for the contents of the urn that contains the smaller amount of coins?

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## BMAD 65

One million dollar coins are thrown into two urns in the following manner: At the beginning of the process, each urn contains one coin. The remaining 999,998 coins are thrown in one by one. Each coin lands into one of the two urns with different probabilities. If at any stage of the process the first urn contains x coins and the second urn contains y coins, then the probabilities that the thrown coin will fall into the first or second urn are:

x/(x+y) and y/(x+y)

The question is: how much should you pay (in advance) for the contents of the urn that contains the smaller amount of coins?

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