BMAD 65 Posted June 17, 2013 Report Share Posted June 17, 2013 How much does the baby weigh if the mother weighs 100 pounds more than the combined weight of the baby and the dog, and the dog weighs 60 percent less than the baby? Quote Link to post Share on other sites

0 Solution Peekay 0 Posted June 17, 2013 Solution Report Share Posted June 17, 2013 25 lbs Quote Link to post Share on other sites

0 BMAD 65 Posted June 17, 2013 Author Report Share Posted June 17, 2013 25 lbs nice work! Please elaborate on your answer. Quote Link to post Share on other sites

0 Pickett 13 Posted June 19, 2013 Report Share Posted June 19, 2013 25 lbs nice work! Please elaborate on your answer. Basic system of equations with 3 variables...from the statements: Let b = baby's weight, d = dog's weight, w = woman's weight... if the mother weighs 100 pounds more than the combined weight of the baby and the dog EQUATION 1: b + d + 100 = w the dog weighs 60 percent less than the baby EQUATION 2: d = 0.4*b and then from the picture, we know EQUATION 3: b + d + w = 170 Then just solve the system Substitute equation 2 into equations 1 and 3: 1) b + 0.4b + 100 = w and 3) b + 0.4b + w = 170 1) 1.4b + 100 = w and 3) 1.4b + w = 170 Then substitute equation 1 into equation 3: 1.4b + 1.4b + 100 = 170 Solve for b: 2.8b = 70 b = 25 Quote Link to post Share on other sites

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## BMAD 65

How much does the baby weigh if the mother weighs 100 pounds more than the combined weight of the baby and the dog, and the dog weighs 60 percent less than the baby?

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