BMAD 63 Report post Posted June 17, 2013 How much does the baby weigh if the mother weighs 100 pounds more than the combined weight of the baby and the dog, and the dog weighs 60 percent less than the baby? Quote Share this post Link to post Share on other sites
0 Peekay 0 Report post Posted June 17, 2013 25 lbs Quote Share this post Link to post Share on other sites
0 BMAD 63 Report post Posted June 17, 2013 25 lbs nice work! Please elaborate on your answer. Quote Share this post Link to post Share on other sites
0 Pickett 13 Report post Posted June 19, 2013 25 lbs nice work! Please elaborate on your answer. Basic system of equations with 3 variables...from the statements: Let b = baby's weight, d = dog's weight, w = woman's weight... if the mother weighs 100 pounds more than the combined weight of the baby and the dog EQUATION 1: b + d + 100 = w the dog weighs 60 percent less than the baby EQUATION 2: d = 0.4*b and then from the picture, we know EQUATION 3: b + d + w = 170 Then just solve the system Substitute equation 2 into equations 1 and 3: 1) b + 0.4b + 100 = w and 3) b + 0.4b + w = 170 1) 1.4b + 100 = w and 3) 1.4b + w = 170 Then substitute equation 1 into equation 3: 1.4b + 1.4b + 100 = 170 Solve for b: 2.8b = 70 b = 25 Quote Share this post Link to post Share on other sites
How much does the baby weigh if the mother weighs 100 pounds more than the combined weight of the baby and the dog, and the dog weighs 60 percent less than the baby?
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