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There was something similar,but I think is not the same.Make both sides equal,to be equation:

1 2 3 4 = 28

2 3 4 5 = 28

3 4 5 6 = 28

4 5 6 7 = 28

5 6 7 8 = 28

6 7 8 9 = 28

You can use all the operations-multiplication ,division, addition,,subtraction... plus brackets,but each digit only ones.

Edited by ash013
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Posted · Report post

There was something similar,but I think is not the same.Make both sides equal,to be equation:

1 2 3 4 = 28

2 3 4 5 = 28

3 4 5 6 = 28

4 5 6 7 = 28

5 6 7 8 = 28

6 7 8 9 = 28

You can use all the operations-multiplication ,division, addition,,subtraction... plus brackets,but each digit only ones.

(-1 + (2 ^ 3)) * 4 = 28

(2 ^ 3) + (4 * 5) = 28

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Posted · Report post

Can the position of numbers be changed?

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Posted · Report post

(1 + (2 * 3)) * 4 = 28 :)

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Posted · Report post

3+4+5-6=-2+8

You didn't say that the 28 couldn't be split!

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Posted · Report post

I've got 3 of them

1+23+4 = 28

(2^3)+(4*5) = 28

?

4*(-5+6)*7=28

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Posted · Report post

(1+(2*3))+4 = 28 (courtesy to 'grey cells')

4*((5*2)-3)) = 28

4*(5 + 6/3) = 28

(4*7)*(6-5) = 28

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Posted · Report post

You can use all the operations-multiplication ,division, addition,,subtraction... plus brackets,but each digit only ones.

I think each digit can be used once suggests the position of the numbers can be changed.

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Posted · Report post

I think each digit can be used once suggests the position of the numbers can be changed.

That was the way I too reasoned . Without repositioning I could not arrive at the result. :)

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Posted · Report post

Can the position of numbers be changed?

Sorry for the delay.Yes.To 3 of them I can't do it without to change the position.If somebody can do it without to change it I would like to see how.

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