BMAD Posted April 16, 2013 Report Share Posted April 16, 2013 What is the expected number of times a fair die must be thrown until all scores appear at least once? Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted April 16, 2013 Report Share Posted April 16, 2013 First number takes only 1 throw Second number takes 6/5 throws (six throws, expect that 5 will be different from first. Third number requires 6/4 throws (same reasoning) Fourth number takes 6/3 throws (ditto) Fifth number takes 6/2 throws Sixth number takes 6 throws. Add them up. 14.7 throws. But the average number of throws required to get all six is less than that, 13 and change. Quote Link to comment Share on other sites More sharing options...
0 dark_magician_92 Posted April 16, 2013 Report Share Posted April 16, 2013 24? Quote Link to comment Share on other sites More sharing options...
0 BMAD Posted April 16, 2013 Author Report Share Posted April 16, 2013 nice try Dark Magician but what is the 'expected wait'? Quote Link to comment Share on other sites More sharing options...
0 Kikacat123 Posted April 16, 2013 Report Share Posted April 16, 2013 6? Quote Link to comment Share on other sites More sharing options...
Question
BMAD
What is the expected number of times a fair die must be thrown until all scores appear at least once?
Link to comment
Share on other sites
4 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.