Posted 9 Apr 2013 A rhombus, ABCD, has sides of length 10. A circle with center A passes through C (the opposite vertex.) Likewise, a circle with center B passes through D. If the two circles are tangent to each other, what is the area of the rhombus? 0 Share this post Link to post Share on other sites

0 Posted 9 Apr 2013 The area is 75 Care to share your solution. 0 Share this post Link to post Share on other sites

0 Posted 9 Apr 2013 Let T be the point of tangency of two circles. The key to the solution is to notice that the points A, B and T are collinear. AT is the radius of the large circle and is perpendicular to the tangency line. BT is the radius of the small circle and is also perpendicular to the tangency line. We know that AB=10, AT=AC and BT=BD, so from this we can conclude that AC=10+BD. Let O be the center of the rhombus. Then BO=BD/2 and AO=AC/2=BD/2+5=BO+5. The area of the rhombus is 2*AO*BO. From AO^{2}+BO^{2}=AB^{2} follows (BO+5)^{2}+BO^{2}=100. Expanding and simplifying we get 2*BO^{2}+10*BO=75 or 2*BO*(BO+5)=75. The left side is actually the area of the rhombus. QED 0 Share this post Link to post Share on other sites

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A rhombus, ABCD, has sides of length 10. A circle with center A passes through C (the opposite vertex.) Likewise, a circle with center B passes through D. If the two circles are tangent to each other, what is the area of the rhombus?

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