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Number game 2


Utkrisht123
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Look at this pair

42 24 ( digits of 42 are interchanged i.e =24)

x 48 x 84 (digits of 48 are interchanged i.e = 84)

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2016 2016

When the digit of multiplicand and multiplier are interchanged then also the result is same.

How many such pair can you find?

If you are asking for 2 digit numbers, then

lets say the numbers are AB and CD, then this property is true if A*C=B*D. eg. 14*82, 24*63 and so on....

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10 pairs in all.



6 of the pairs are truly 2 digit number pairs:
1. (12, 42 ) (21, 24)
2. (13, 62 ) (31, 26)
3. (14, 82 ) (41, 28)
4. (23, 64) (32, 46)
5. (24, 84) (42, 48) ... already listed
6. (34, 86) (43, 68)

4 additional the pairs can be had where there is a 1 digit number in each pair e.g. you take 1 as 01 and the reversing digits you get 10
). These are
a. (1, 20) (10, 2)
b. (2,40) (20,4)
c. (3,60) (30,6)
d. (4,80) (40,8)

I guess this is it.

Didn't get into 3 digit numbers because rules of switching digits as shown in example gets cloudy

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10 pairs in all.

6 of the pairs are truly 2 digit number pairs:

1. (12, 42 ) (21, 24)

2. (13, 62 ) (31, 26)

3. (14, 82 ) (41, 28)

4. (23, 64) (32, 46)

5. (24, 84) (42, 48) ... already listed

6. (34, 86) (43, 68)

4 additional the pairs can be had where there is a 1 digit number in each pair e.g. you take 1 as 01 and the reversing digits you get 10

). These are

a. (1, 20) (10, 2)

b. (2,40) (20,4)

c. (3,60) (30,6)

d. (4,80) (40,8)

I guess this is it.

Didn't get into 3 digit numbers because rules of switching digits as shown in example gets cloudy

pure 2 digit pairs - 12

and tohose which have a 1 digit number as well as above - 4

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