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One's divisibility


Prime
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3333....3 is 3*1111....1

The number consisting of only ones must be a multiple of 3 and 1111...1. For it to be a multiple of 111....1, it must be a multiple of 100 1's long. The first multiple of 100 divisible by 3 is 300. So, the number is 111...1 with 300 1's.

That's the number I was looking for!

Edited by Prime
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