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Stampless Foreheads

Question

Yoruichi-san    116

Feeling left out, as everyone else around here seems to be running around with various polychromatic items attached to their foreheads, you and I decided to play a friendly variant of Indian Poker. Because I'm partial to pointy things that resemble weapons, I take all the spades (13 cards) from a standard 52 card deck, shuffle them, and deal us each one. We each then affix the card to our distinctly-bare-up-until-now foreheads without looking at our own cards. Then we take turns declaring "higher" (if we think our card is higher than the other's), "lower" (if we think our card is lower than the other's), or we say "pass" (if we don't know). Since you and I both hate to be wrong, neither will declare unless we have a logical reason to do so.

What is the maximum number of iterations it will take before one us can declare?

4 answers to this question

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k-man    26

A: "Pass" unless B has 2 or A

B: "Pass" unless A has 2,3,K or A

A: "Pass" unless B has 3,4,Q or K

B: "Pass" unless A has 4,5,J or Q

A: "Pass" unless B has 5,6,10 or J

B: "Pass" only if A has 8

At this point A will declare as he knows he has an 8. B should have 7 or 9 for this to continue for so long.

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bonanova    76

A logical reason for the first declare is the other's card is above or below the average value for a suit: the seven of spades. If it is the seven we say idk. Based on that response and what the opponent sees, s/he replies with similar logic and eventually the process converges.

I'm gonna make a wild guess before going through the analysis and say seven iterations.

But halving the intervals each time might make it four. Idk.

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Nice puzzle, nice solve!

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Yoruichi-san    116

Yep, just a simple little puzzle that I thought of on my way to something massively more complicated...

Indian Head Go Fish ;P

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