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I'll tell you what my thinking was when I said 23.

2,5,11,__, 137

2+3=5, 5+6=11, 11+12=23, 23+24=47 (which, not understanding bases & binary, I assumed was equal to 137)

Good logical reasoning , Nikyma. But as you have said 47 is not 137. ;)

EDIT : Just saw your other post .

If it was every other alternate prime number , it would have been too easy . ;)

I hope now that the answer is known , someone will solve the reasoning part. :)

Edited by grey cells
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Waiting for the explanation. :) This one's easy . So I am not giving the explanation .

The answer is 17.(for those who don't want to go through previous posts). :lol:

Please post the next number in the sequence.

Let's see if someone gets the logic.

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I did notice one thing, and I think I'm on the right track, but not all the way there yet.

If you list the numbers in order like this....

2

5

11

17

137

149

173

but in binary, they make this...

00000010

00000101

00001011

00010001

10001001

10010101

10101101

From this you can notice that each line is only different from it's previous line by exactly 3 digits every time. I guess the pattern would then be to change 3 digits and still be prime. If this rule sticks, I think it means the next number would be 197.

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I did notice one thing, and I think I'm on the right track, but not all the way there yet.

If you list the numbers in order like this....

2

5

11

17

137

149

173

but in binary, they make this...

00000010

00000101

00001011

00010001

10001001

10010101

10101101

From this you can notice that each line is only different from it's previous line by exactly 3 digits every time. I guess the pattern would then be to change 3 digits and still be prime. If this rule sticks, I think it means the next number would be 197.

observation , AI . :D It definitely looks that way .

But the next number , according to my reasoning is incidently not 197. :)

But your representation of 8 bits is spot-on. :lol:

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observation , AI . :D It definitely looks that way .

But the next number , according to my reasoning is incidently not 197. :)

But your representation of 8 bits is spot-on. :lol:

Is it higher or lower than 197?

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I did notice one thing, and I think I'm on the right track, but not all the way there yet.

If you list the numbers in order like this....

2

5

11

17

137

149

173

but in binary, they make this...

00000010

00000101

00001011

00010001

10001001

10010101

10101101

From this you can notice that each line is only different from it's previous line by exactly 3 digits every time. I guess the pattern would then be to change 3 digits and still be prime. If this rule sticks, I think it means the next number would be 197.

am sorry that I didn't mention this in my previous posts . But I think it is almost a giveaway to the reasoning . But to be fair to you all ,I will give a hint . :)

Now for the first 16 dec. numbers from 0 to 15 , the maximum number of bits used is 4 . So leave it at that.

For the numbers after 15 , obviously the number of bits used are more than 4 . So for only these numbers , we have to use AI's representation . ;)

Sorry AI , I didn't say this beforehand . But as I have mentioned , this is a big hint. :)

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