There are 5 bags, of which one contains 4 blue balls, one contains 3 blue balls and 1 red ball, one contains 2 blue balls and 2 red balls, one contains 1 blue ball and 3 red balls, and the last contains 4 red balls. You do not know which bag has which distribution.

You will be allowed 10 draws, each from any bag of your choosing, and your goal is to draw as many of the same colored balls as possible.

What is your play (by which, I am assuming you're a probabilistic optimalist, like me )?

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## Yoruichi-san 116

Perpetuating the puzzle propagation:

There are 5 bags, of which one contains 4 blue balls, one contains 3 blue balls and 1 red ball, one contains 2 blue balls and 2 red balls, one contains 1 blue ball and 3 red balls, and the last contains 4 red balls. You do not know which bag has which distribution.

You will be allowed 10 draws, each from any bag of your choosing, and your goal is to draw as many of the same colored balls as possible.

What is your play (by which, I am assuming you're a probabilistic optimalist, like me )?

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