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Arrengement

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Hi friends...

I aarenged the numbers 1,2,3,......to 7 according to a specific way,and I got this :

2,3,4.1,6,5,7

when I added one more number,number 8 ( 1 to 8 )I got this :

5,6,8,1,7,4,3,2

and by adding number 9 to the series I got:

6,5,4,1,9,3,8,2,7

Now my question is, which combination we will get in case of 10 numbers?

( you should find my way of arrengement) :rolleyes::ph34r:

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Posted · Report post

Till now....No answer....is it so hard?!

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Posted · Report post

Hi Wolfie.....great to see you again...

I've been thinking on this. Still thinking.

Don't worry that you're getting no answers. Things have been slow for the last 2 - 3 days. They will pick up.

Still thinking!

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Posted · Report post

Hi Wolfie.....great to see you again...

I've been thinking on this. Still thinking.

Don't worry that you're getting no answers. Things have been slow for the last 2 - 3 days. They will pick up.

Still thinking!

Hi dear Fabig...happy to meet u again....I missed u all
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Posted · Report post

quick question, i doubt it will help, but

are you taking the series 1,2,3,4,5,6,7,8 and applying the rule,

or the series 2,3,4,1,6,5,7,8 and applying the rule?

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Posted · Report post

quick question, i doubt it will help, but

are you taking the series 1,2,3,4,5,6,7,8 and applying the rule,

or the series 2,3,4,1,6,5,7,8 and applying the rule?

I took the series 1,2,3,4,5,6,7 and by applying my mothod I got the above mentioned combination.

then 1,2,3,4,5,6,7,8, I did the same getting another combination

and 1,2,3,4,5,6,7,8,9, the same

your turn is to take the series: 1,2,3,4,5,6,7,8,9,10 to tell me which combination will come out of them.

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4,9,10,1,3,6,8,2,5,7

1

2,1

1,3,2

2,4,3,1

5,3,2,1,4

4,2,5,1,3,6

For the next number, start at the position of the last number, and moving circularly to the right skip over a number of empty spots equal to the number of letters in the name of the number to be placed.

1 is always in the 4th spot (if it exists) because it gets first choice and has 3 letters in the name 'one.'

2 is always in the 8th spot (if it exists) because it is 4 spots from spot 4, which means 3 need to be skipped which is the number of letters in 'two.'

etc.

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4,9,10,1,3,6,8,2,5,7

1

2,1

1,3,2

2,4,3,1

5,3,2,1,4

4,2,5,1,3,6

For the next number, start at the position of the last number, and moving circularly to the right skip over a number of empty spots equal to the number of letters in the name of the number to be placed.

1 is always in the 4th spot (if it exists) because it gets first choice and has 3 letters in the name 'one.'

2 is always in the 8th spot (if it exists) because it is 4 spots from spot 4, which means 3 need to be skipped which is the number of letters in 'two.'

etc.

wooooooow !!!! very good ! you got it....
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