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Posted (edited) · Report post

or even

2*4*108

So should we now just select 6 random numbers - plus the target? ( that's not a complaint, just a possible natural evolution of the game). It seems that the old format was gettin a bit easy

Edited by fabpig
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Posted · Report post

i say 2 random 2 digits and 4 random 1 digits if thats fine.

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Posted · Report post

I agree. So

3, 4, 7, 9, 21, 54 477

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Posted · Report post

54*9-(21/7*4)+3 = 477

I think it is more challenging to have to use all 6 numbers

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Posted (edited) · Report post

(54 - (4-3)) x 9 = 477

dang it, curr3nt!!!

^

edit

Edited by TheCube
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Posted · Report post

You can pick numbers Cubie

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Posted · Report post

no, you got the most numbers in the equation you should go.

Hey, should we count if all numbers are used?

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Posted · Report post

So that if someone reaches the total with all the numbers he beats someone who reached the total using only some of the numbers?

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Posted (edited) · Report post

I just think all numbers must be used to reach the total period. Some of the answers are easy if you can just use a few. Trying to make them all work is more challenging. *shrug* You all can do what you want but my future answers I'm going to use all the numbers. So there.

2, 3, 5, 8, 13, 21 ?= 987

--edit--

The count of numbers used might not work because if you got it with say 4 numbers how long would you wait to know it was your turn?

Edited by curr3nt
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Posted · Report post

I agree it has been a bit too easy so far.

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Posted · Report post

(21)(8*5 + (13 - 3*2)) = 987

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Posted · Report post

@TheCube: Cubie you need to post the next set of numbers.

@All: Do we agree that we have to use all the numbers?

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Posted · Report post

alright

473

4, 2, 9, 1, 84, 14

and yes, use all numbers i say.

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Posted · Report post

84*4+(9+1)*14-2 = 474

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Posted · Report post

(84-14+9)(4+2)-1=473

am working on the next. that part's harder than the solve. be right back.

didnt try to solve this one, just worked backwards from one solution, so it might be easy. or it might be not....

1, 2, 7, 9, 31, 75 = 369

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Posted · Report post

75+(31*9)+(2*7)+1 = 369

I prefer to just make up numbers.

1, 3, 5, 7, 11, 13 ?= 444

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Posted · Report post

(13*3-7+5)(11+1)=444

1,2,3,4,10,11 = 999

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Posted · Report post

(11*10+1)*(2+3+4)

3,5,8,9,13,60 = 782

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Posted · Report post

-3*5+8+9+13*60=782

4,5,11,34,8,9 = 258

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Posted · Report post

(34+11+5)(9-4)+8=258

8, 5, 2, 9, 82, 37 = 741

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Posted · Report post

(82+8)*9+5-37*2=741

this one should be a little harder...

5, 9, 8, 7, 56, 37=703

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Posted · Report post

(37)((56+9*8+5)/7)=703

5, 1, 7, 3, 92, 74 = 981

btw, are you Nana7 from Mafiamaniac, Nana77?

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Posted · Report post

(74+92)*(7-1)-(5*3) = 981

6, 7, 8, 9, 10, 42 = 783

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Posted (edited) · Report post

btw, are you Nana7 from Mafiamaniac, Nana77?

Yes. My Nana7 account here was lost in the crash months back and I did not feel it worth the trouble of reviving.

and Hi Curr, nice to see ya. :)

Edited by nana77
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Posted (edited) · Report post

hmm, within 1 point

(10+6)*(42+8)-7-9=784

:duh:

can numbers be combined like 6,7 into 67 or 76?

Edited by nana77
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