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Rabbit Hutch

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Look also on my solution with scales it is alternatve to your solution.

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Posted · Report post

Yes If it is in 2d your solutions is wrong.

Maybe rabbits will have enough space ;-) but it will be less than on the begining.

I have not mentioned anything about enough space ... less does not mean not enough ... btw, have you seen a rabbit that would fit into your or my image?

ps: have you noticed that your solution is not made of matchsticks of the same size? check the hypotenuses

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Posted · Report post

If you are so smart give my solution of this problem triangle A1A2A3 is make one plane A and is formated on platen plane Z, triangle B1B2B3 is make the second plane B and is formated on plated plane x , plane Z is perpendicular to plane X finde the cuting edge of Tr A1A2A3 & B1B2B3 (all is in 3d of course)

post-2962-1197837744_thumbgif

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Posted · Report post

If you are so smart give my solution of this problem triangle A1A2A3 is make one plane A and is formated on platen plane Z, triangle B1B2B3 is make the second plane B and is formated on plated plane x , plane Z is perpendicular to plane X finde the cuting edge of Tr A1A2A3 & B1B2B3 (all is in 3d of course)

good luck with your homework

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Posted · Report post

This is so easy dont think just try ;-)

I know the solution and I will give it in next week bye.

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^ Please don't. This thread is to discuss the riddle in the OP, not new geometry problems you'd like to introduce.

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The dispute Kro-G offers is incorrect, the administrator's solution is correct. For one, there is a congruence shortcut in triangles stating that if three sides in one triangle are congruent to three corresponding sides in another triangle, then the two triangles are congruent. Each of the six triangles in teh larger hexagon is an equilateral triangle, all with the same side length. Therefore, according to this congruence shortcut, the triangles are the same side (see Euclid's Elements I)

Moreover, the area calculation was incorrect also. You do not find the area of a triangle by multiplying the base and an arbitrary leg by one half (in this case, a * a, since both are the same length in an equillateral triangle). The area is found by multiplying a leg (a) by the perpendicular height (which lends itself to the Pythagorean theorem resulting in an altitude of a*sqrt(3)) to the vertext opposite your chosen leg, and then multiplying that by one half.

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The dispute Kro-G offers is incorrect, the administrator's solution is correct. For one, there is a congruence shortcut in triangles stating that if three sides in one triangle are congruent to three corresponding sides in another triangle, then the two triangles are congruent. Each of the six triangles in teh larger hexagon is an equilateral triangle, all with the same side length. Therefore, according to this congruence shortcut, the triangles are the same side (see Euclid's Elements I)

Moreover, the area calculation was incorrect also. You do not find the area of a triangle by multiplying the base and an arbitrary leg by one half (in this case, a * a, since both are the same length in an equillateral triangle). The area is found by multiplying a leg (a) by the perpendicular height (which lends itself to the Pythagorean theorem resulting in an altitude of a*sqrt(3)) to the vertext opposite your chosen leg, and then multiplying that by one half.

My apologies, the altitude is .5*a*sqrt(3). And this has already been addressed by teh administrator anyway.

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Posted · Report post

I've done this one in 11. No overlap and no breaking matchsticks in half.

post-4117-1201842071_thumbjpg

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Ever wonder why matchsticks are used and not poles or anything else? If you are to make a rabbit pin with 12 matchsticks, the rabbits would be awfully small. Plus, matchsticks catch on fire easier than regular sticks.

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After i did the courting of the original solution i found that i used 13 matchsticks:

post-5809-1206850948_thumbgif

So the first thing flashed into my mind is if i can shorten just one single matchsticks then i can be done.so there for my 1st solution is :

post-5809-1206850545_thumbpng

But since building up a dwelling for those rabbits is what we concerted, then perhaps we are not supposed to put rabbits in the air and a two-dimensional solution should be better....

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Rabbit Hutch - Back to the Matchstick Puzzles

In the picture there are little flats for 6 rabbits. Can you build a dwelling for these 6 rabbits with only 12 matches. Each rabbit must have an equally big space.

Edit: 6 separate flats are needed for the rabbits.

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Rabbit Hutch - solution

Picture added as per below hint.

post-2-1177069379_thumbgif

easier way, just make a cube...

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In general this problem can be resolved for as: N matches, with K spaces, to determine K spaces with to N-1 matches, where N is 12. You can then try N=9, N=5, and get N-1 edges to create the same amount of closures as in the initial state :mellow: Therefore by resolving this problem for 5 edges (matches), 2 spaces; then 4 spaces, and 9 edges, and 6 spaces, 12 edges (matches), you get the trick to resolved it for all. A triangle -> hexagon figures could be combined with all the matches.

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Posted · Report post

how about only using 7

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This is what I came up with:

post-10319-1223059235_thumbgif

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I have not mentioned anything about enough space ... less does not mean not enough ... btw, have you seen a rabbit that would fit into your or my image?

post-10350-1224855390_thumbgif

Sure... B))

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Posted · Report post

heres the solution i came up with. i was impressed by everyone's creativity on this one

post-13077-1231877136.jpg

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