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Crossing the River


wolfgang
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Two families(1 and 2),each consists of 5 persons(Father,Mother, Son,Daughter,and Baby).

Family 1 is at the right side of the riverĀ®,and Family 2 at the left side of the river(L).

They want to change places.

There is only one boat with its driver,the boat will not cross the river unless there are three persons on board(baby is one person).

Each father should pay 5$ for each single cross, each mother 4$,each son 3$,each daughter 2$,and each baby 1$.

Both families have a total of 33$.

Any baby should be accompanied with any one of his family.

How can they change their places using that amount of money?

they should use the boat only.

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can i ask one thing?? is there a limit in max no. of persons that can travel in the boat at a time mentioned?? only the minimum is mentioned... so one family can go together. costs only 15... hi hi.. prob solved

But from wolgang's post (post #16), he says ----

The total sum is 33$ for the both two families( i.e.the money ,33$,are devided between them,...somehow...)

The boats driver must be always on his boat.

The boat can take only four persons each time( no more and no less),i.e.the boat driver and exactly three persons.

Each baby must be accompanied with ,at least,one person of his own family.

Edited by thoughtfulfellow
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First in Family A son Daughter and baby will get in the boat and cross the river and B's son daughter and baby will get in it(3+2+1)*2=12rs

next dad mom and baby interchanges in same manner (5+4+1)*2=20

20+12=32rs

:P am i correct

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this riddle is impossible......

for exchanging the places .. family need 30$ but as only 3 of them can go at a time... one of them has to make 3 trips... which only the baby can make for 2 extra dollars( daughter requires 4 extra dollars) .... but if he makes 3 trips ... another family member has to also make 3 trips which is not possible......

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Some inconclusive analysis

1. If we had no restrictions as to number of pasengers, minmum crossing fee would be $5+$4+$3+$2+$1 = $15 for each family. A total of $30.

2. In order to insure 3 passengers on every trip, someone must travel across the river, back to original side and another trip to get to the desired side.

3. With the $33 limit, this person crossing both ways extra must be the baby.

A very goog approach!!
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this riddle is impossible......

for exchanging the places .. family need 30$ but as only 3 of them can go at a time... one of them has to make 3 trips... which only the baby can make for 2 extra dollars( daughter requires 4 extra dollars) .... but if he makes 3 trips ... another family member has to also make 3 trips which is not possible......

No. dear it is not impossible.....you solve it in your first trial without knowing that .

the secret behind this puzzle is that the two babies are twins!!!

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