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Ma physics teacher gave me this a while back, took me a while to solve. M not dhat smart but i want to find another way of solving it. x=yz + (1/2)y(z)2. Make z d subject of 4mula....thankz

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Posted (edited) · Report post

Since 1/2 and 2 cancel.

x = yz + yz

x = 2yz

z = x/2y

So... why is the physics teacher giving math problems?

-edit-

forgot spoilers.

Edited by curr3nt
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Posted · Report post

Itz actually a physics 4mula, i just changed the letters so that one might not notice cuz itz very common. Your answer would've been right if the '2' meant 'x2', it actually means 'raised to the pwr of 2'.....sorry, my mistake

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Posted · Report post

Is this the formula?

x = (y * z) + (y * z^2)/2

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Posted · Report post

z= -1+sqrt[1+(2x/y)], and z= z= -1-sqrt[1+(2x/y)]

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Posted · Report post

The closest physics formula I can find is s = vt + at2/2 but v <> a so how can they both be y?

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Posted · Report post

x = yz + yz2/2

2x/y = z2 + 2z

2x/y + 1 = z2 + 2z + 1

2x/y + 1 = (z + 1)2

±√(2x/y + 1) = z + 1

z = ±√(2x/y + 1) - 1

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Posted · Report post

Why do you insist on doing other people's homework?

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Posted · Report post

@Curr3nt, thankz alot, whew, so there's another way...bt stil kinda d same (based on quadratics), bt stil diff @thechad, lol

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Posted · Report post

Why do you insist on doing other people's homework?

I insist? Normally I do not insist. As for this one... it seemed not to be actual homework. I choose this time to believe he was checking his work.

And if he actually lied then I figure class will get quite a bit interesting if he doesn't actually learn how to work with equations.

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Posted · Report post

I think this is a Physics formula

S = ut + 1\2 at2

Here, both u and a are same, that is initial spped and acceleration are same.

This is possible only when the the object is still(not moving)

So, S = 0*t + 1/2 * 0 * t2 = 0

or

at time, t=0

So, S = u * 0 + 1/2 *a * 02 = 0

So, the subject can go like, AT TIME 0(INITIALLY) :)

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