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wolfgang

Question

I built a killing machine which will kill these three persons : John, Sam,and Bill...

My machine will obay my orders in form of codes,

So ,I want john to be killed on monday,,I`ll give this order:-

NPFIZJ EDIH HKCK....( which means...monday kill john).

HTBOIZQ SDRGF LOR(tuesday shoot sam).

YUEYVI QPIV MDIZ ( lastly hang bill).

who can stop me?

The only order which can stop my machine is to give a code for(Abort operation).

Muuuuhahahaaaaaaa

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No luck so far, buy some methods I've tried. Not seeing the pattern yet....

Numbers correlate to a positional alphabetic shift. (ie, N to K = -3)

1 1 -8 5 25 -15 -5 -5 -3 -4 -2 -4 -5 -3

N P F I Z J E D I H H K C K

M O N D A Y K I L L J O H N

-7 -1 -3 -4 5 25 -8 0 -4 3 8 14 7 14 5

H T B O I Z Q S D R G F L O R

T U E S D A Y S H O O T S A M

13 -19 14 5 10 -15 9 15 -5 15 11 -5 -3 12

Y U E Y V I Q P I V M D I Z

L A S T L Y H A N G B I L L

A B O R T O P E R A T I O N

And here, the list of letters used, in the order they occur

A Z Z O U P

B M

C

D I I

E B

F

G V

H C D Q

I D D

J H

K E

L I H Y V I Z

M N R

N F K I

O P K R G

P

Q

R

S O S L E

T H F Y

U T

V

W

X

Y J Q I

Z

Edited by bekabeh

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i would have just shot the machine until it died only to hear in its final words "I'll be back!"

:P

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No luck so far, buy some methods I've tried. Not seeing the pattern yet....

Numbers correlate to a positional alphabetic shift. (ie, N to K = -3)

1 1 -8 5 25 -15 -5 -5 -3 -4 -2 -4 -5 -3

N P F I Z J E D I H H K C K

M O N D A Y K I L L J O H N

-7 -1 -3 -4 5 25 -8 0 -4 3 8 14 7 14 5

H T B O I Z Q S D R G F L O R

T U E S D A Y S H O O T S A M

13 -19 14 5 10 -15 9 15 -5 15 11 -5 -3 12

Y U E Y V I Q P I V M D I Z

L A S T L Y H A N G B I L L

A B O R T O P E R A T I O N

And here, the list of letters used, in the order they occur

A Z Z O U P

B M

C

D I I

E B

F

G V

H C D Q

I D D

J H

K E

L I H Y V I Z

M N R

N F K I

O P K R G

P

Q

R

S O S L E

T H F Y

U T

V

W

X

Y J Q I

Z

I was thinking positional shift after a redistribution of letters in the style of wolfgang's earlier money making scheme algo... but I'm too lazy to check it.

EDIT: Try 6 permutations.

Edited by Molly Mae

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Every time I think I see some pattern, then I see a conflict in the pattern. Very clever coding.

Has the Abort Operation code starting with u. Am I any where near the right track?

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Every time I think I see some pattern, then I see a conflict in the pattern. Very clever coding.

Has the Abort Operation code starting with u. Am I any where near the right track?

No,,,,It starts with( D )

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Well, you haven't given the order yet so 'll just have to find you and kill you

you did say who can stop ME not the machine XD

lol...well thank you dear...I am ready

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give to each alphabetical letter ( A to Z) a number(1 to 26)...then........

I`ll not say anything more....find it your self...

by the way.....john is dead...

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Next Tuesday,Sam will be killed....hahahaaaaaaaa

Do something.....

(put the alphabet in a form of circle...and give to each letter a number...then........!!!)

note: I gave my machine an order..(OCFF UNWP IAQP) which means..( Rest five days).

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abortoperation

d?????????????

day in monday

izj

sday in tuesday

oizq

day in days

iaq

Does the alphabet/number map change after using a letter?

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abortoperation

d?????????????

day in monday

izj

sday in tuesday

oizq

day in days

iaq

Does the alphabet/number map change after using a letter?

As an example, there are 6 As, 6 Ls, and 6Ss in the inputs. The outputs, however, do not contain 6 of any number (there are 7 Is, 4 Fs, 4 Ps, etc.). So the at least As, Ls, and Ss can't always map to the same letter, because that would have produced at least three sets of 6 of the same letter in the output.

It's driving me nuts that I can't figure out how the mapping changes. Another hint wolfgang, not really sure what putting the alphabet in a circle is meant to do?

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As an example, there are 6 As, 6 Ls, and 6Ss in the inputs. The outputs, however, do not contain 6 of any number (there are 7 Is, 4 Fs, 4 Ps, etc.). So the at least As, Ls, and Ss can't always map to the same letter, because that would have produced at least three sets of 6 of the same letter in the output.

It's driving me nuts that I can't figure out how the mapping changes. Another hint wolfgang, not really sure what putting the alphabet in a circle is meant to do?

You are welcome...(MYO TOK YVAUQEG)

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hopefully this will help

magicnumbersofnumerolog.jpg

Hint :-

a.........will be (B)

b..........will be (D)

ab........will be (D)

ba........will be (E)

c..........will be (F)

abc......will be (G)

bac......will be (H)

cab......will be (I)

Is this enough?

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then cba is I?

If I am seeing the pattern, I would believe cab=J. Trying different systems to satisfy a=B; b=D and c=F. Come out with d=H or d=I and e=J or e=M. But run into conflicts with given translations of initial letters in each command.

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Hint :-

a.........will be (B)

b..........will be (D)

ab........will be (D)

ba........will be (E)

c..........will be (F)

abc......will be (G)

bac......will be (H)

cab......will be (I)

Is this enough?

Sorry...I made a big mistake here....the correct code will be like this:-

ab....will be(DE)

ba....will be(ED)

abc....will be(DGG)

bac....will be(EEH)

cab....will be(GDG)

I am so sorry...was my bad :duh:

Edited by wolfgang

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he did say the code will start with d so I'm guessing it starts with DE unless abo will change the code

da has appeared IZ twice

both cab and abc had 2 g's and one d, the d being a both times

whenever a is at the start it appears as D

whenever b is at the start it appears as E but in bill it appeared M

whenever c is at the start it appears as G

Still going the wrong way, and I don't see the circle helping.....

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