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wolfgang

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if x resides in the range [0.5,1.5) (i.e. rounds to 1) then when multiplied by 2 (equivalent of being added to itself as 3+3=6 == 3*2=6) the resulting range is [1,3). We can split this range to produce the values 1, 2 and 3 when rounding occurs:

[1,1.5) rounds to 1

[1.5,2.5) rounds to 2

[2.5,3) rounds to 3

Dividing each range by 2 results in the starting ranges of x:

[0.5,0.75) * 2 = [1,1.5) < 2

[0.75,1.25) * 2 = [1.5,2.5) = 2

[1.25,1.5) * 2 = [2.5,3) > 2

Edited by Egghead

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may be wrong ,in the triangle the Triangle inequality ,where the sum of the lengths of any two sides is greater (or equal to ) than the lenght of the third remaining .

so if we have an ABC triangle ,AB= 1 AC = 1

we always have AB+AC > BC

meaning 1 + 1 > 2

i hope it's true

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If 1 perfectly equals 1 then 2 1's make a 2

since life is full of inequalities what a person considers one may not equal what another person calls 1

if I get 2 big apples that will be 2 apples

but if i get 2 small ones that would also make 2 apples

so 1 small apple +1 small apple < 2 big apples and

1 big apple +1 big apple > 2 small apples

Unless you define what is "1 apple" the theory is correct

I don't know....

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If 1 perfectly equals 1 then 2 1's make a 2

since life is full of inequalities what a person considers one may not equal what another person calls 1

if I get 2 big apples that will be 2 apples

but if i get 2 small ones that would also make 2 apples

so 1 small apple +1 small apple < 2 big apples and

1 big apple +1 big apple > 2 small apples

Unless you define what is "1 apple" the theory is correct

I don't know....

well,,big apple...is big and small apple is small....they are not equall.

what about equall volumes?..... :blink:

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if you use the letters and add it up

o- 15

n- 14

e- 5

all of that added up and doubled (34) is a less than

t-20

w-23

o-15

which is 58

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well,,big apple...is big and small apple is small....they are not equall.

what about equall volumes?..... :blink:

but both are still considered as "apples" under the category of an apple generally

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Another wild guess

starting with

1+1 comparing to 2

then writing as:

one plus one comparing to two

we can translate each letter into the equivalent of its position in the alphabet (a=1, b=2, c=3 ...) and add each side to arrive at

136 > 58

Carry this further by adding 1+3+6 and 5+8 and we have

10 < 13

Yes, a bit off beat!

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Another wild guess

starting with

1+1 comparing to 2

then writing as:

one plus one comparing to two

we can translate each letter into the equivalent of its position in the alphabet (a=1, b=2, c=3 ...) and add each side to arrive at

136 > 58

Carry this further by adding 1+3+6 and 5+8 and we have

10 < 13

Yes, a bit off beat!

I like your way of thinking....

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Yes....less than two litres...

now try with more than two...

but 1 litre of water does not equal 1 litre of alcohol

it's like adding 1x to 1y

if this works the so do the apples

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but 1 litre of water does not equal 1 litre of alcohol

it's like adding 1x to 1y

if this works the so do the apples

by adding equal volumes,let us say 1 volume (X) +1 volume(Y) = 2 volumes

but in some cases,are not equal to 2, as I mentioned before.

It is the same by adding equal wieghts,,,1Kg(x)+1Kg(y)= 2 Kg

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Two substances of the same mass may react to form a substance with less mass. Looking strictly at mass and neglecting the energy gained or lost, you can have a final product of greater or less mass that the original reactants.

EDIT: I guess the aforementioned example (see spoiler) applies to the volume as well.

Edited by Faizaan

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Boolean algebra: 1 + 1 = 1

Galois field 2: 1 + 1 = 0

Subspaces: 1 subspace + 1 subspace = 1 subspace

Sand: 1 pile + 1 pile = 1 pile

Speed of light: 1 c + 1 c = 1 c

Networks: power of 1 component + power of 1 component < power of (1 component + 1 component)

Problems: 1 small problem + 1 small problem = RAGE

Memorisation: time taken to learn something twice as long

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Boolean algebra: 1 + 1 = 1

Galois field 2: 1 + 1 = 0

Subspaces: 1 subspace + 1 subspace = 1 subspace

Sand: 1 pile + 1 pile = 1 pile

Speed of light: 1 c + 1 c = 1 c

Networks: power of 1 component + power of 1 component < power of (1 component + 1 component)

Problems: 1 small problem + 1 small problem = RAGE

Memorisation: time taken to learn something twice as long

yes...and there are alot more!

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If a person learns a foreign language, then he knows two languages (his mother tongue and the new language). So if a native English speaker learns American, he now knows two languages, but since English and American although different are essentially variants of the same language, he knows less than two languages.

In this case 1 + 1 < 2.

If a native Italian speaker learns English, he then knows two languages, but at the same time he can communicate with native speakers of USA, Australia, and all other English-speaking countries, as though he knew more than two languages.

In this case 1 + 1 > 2.

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