[Guest]

Two jugs contain a certain amount of lemonade. If you pour from the first jug as much

lemonade into the second jug as the second jug had, then you pour from the second jug

as much lemonade into the first jug as the first jug just had, and finally you pour from the

first jug as much lemonade into the second jug as the second jug just had, then both jugs

will contain 160 liters of lemonade (in each). How much lemonade did the second jug

contain originally?

[Guest]

Second Jug 100 litres

First Jug 220 litres

[Guest]

Let x equal amount in first jug, y equal amount in second jug.

At start: x + y = 320

First pour: (x-y) + (2y) = 320

Second pour: (2x-2y) + (3y-x) = 320

Final Pour: (3x-5y) + (6y-2x) = 320

therefore 3x-5y = 160 = 6y-2x

5x=11y

5(320-y) = 11y

16y=1600

y =100

Edited October 20, 2011 by agowenlock

[Guest]

Nicely done! Thank you!