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The letters used in the words below were randomly assigned a value (1-18). Words are given values that are the product of the values assigned to them. For instance, if C=2, A=1, and T=7, then CAT = 14.

What is the value of “las vegas” if the following are true:

Gamble = 1,297,296

Roulette = 917,280

Craps = 77,760

Drunk = 108,800

Strong = 23,760

Blackjack = 207,028,224

Stop = 810

Tossed = 57,834

Love = 2,548

As a side note, what do you call this type of puzzle? I’d like to title it with the type of puzzle it is, but can’t figure out what to call it

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I would call this puzzle an Alphamultiplic Puzzle. I made that up.

I'd like to suggest showing the prime factorization of the values in order to make it easier on solvers.

In this case the clues would look like:

Gamble = 1,297,296 = 24·34·7·11·13

Roulette = 917,280 = 25·32·5·72·13

...etc...

But this is your baby, so it's entirely up to you.

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Originally, I started doing this a way to waste a lot of time doing factor trees by hand. I'm guessing you're right that most people aren't looking for that ;)

Gamble = 1,297,296 = 2^4 * 3^4 * 7 * 11 * 13

Roulette = 917,280 = 2^5 * 3^2 * 5 * 7^2 * 13

Craps = 77,760 = 2^6 * 3^5 * 5

Drunk = 108,800 = 2^8 * 5^2 * 17

Strong = 23,760 = 2^4 * 3^3 * 5 * 11

Blackjack = 207,028,224 = 2^16 * 3^5 * 13

Stop = 810 = 2 * 3^4 * 5

Tossed = 57,834 = 2 * 3^5 * 7 * 17

Love = 2,548 = 2^2 * 7^2 * 13

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Alright, so there are actually TWO solutions to this puzzle...both satisfying the original words (this might be why this one took me much longer than the last one to solve...) Good puzzle though!!!

LAS VEGAS = 367,783,416 using the following substitutions:

A = 18

B = 12

C = 4

D = 17

E = 7

G = 11

J = 1

K = 16

L = 13

M = 6

N = 5

O = 2

P = 15

R = 8

S = 9

T = 3

U = 10

V = 14

OR LAS VEGAS = 40,864,824 using the following substitutions:

A = 6

B = 12

C = 24

D = 17

E = 7

G = 11

J = 1

K = 8

L = 13

M = 18

N = 10

O = 2

P = 15

R = 4

S = 9

T = 3

U = 20

V = 14

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