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Sixy Rollo


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DELETE = 2

E is not 2nd - REBUTS = 0

L is not 3rd - DELATE = DEBATE

E is not 4th - DELATE = DELETE

E is 5th

T is not 6th - REBUTS = 0

so D is 1st or E is 7th

REBATE

if 1 then D is not 1st as REBATE = DEBATE, so E is 7th

if 0 then D is 1st as D - > R would be only change from DEBATE = 1

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???E?E

DELETE - 2 	REMOVE - 1 	REBUTS - 0 

MALEIC - 1 	REBELS - 1 	REBATE - 1 

DELATE - 1 	FREEZE - 2 	STREAK - 2 

DEBATE - 1 	REMOTE - 1 

DENOTE - 1 	ALMOST - 0 


Score Changes: Yodell +5, maurice +5

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SPHERE

DELETE - 2 	REMOVE - 1 	REBUTS - 0 

MALEIC - 1 	REBELS - 1 	REBATE - 1 

DELATE - 1 	FREEZE - 2 	STREAK - 2 

DEBATE - 1 	REMOTE - 1      SERENE - 3

DENOTE - 1 	ALMOST - 0 


Score Changes: Yodell +5, maurice +5, TheCube +25, WbB +14

WomBatBreath - 664

Fabpig - 232

Thalia - 175

Maurice - 160

curr3nt - 121

Quag - 105

JDave - 100

TheCube - 120

Marquis - 78

Yodell - 25

Aaryan - 15

Benjer3 - 10

dawh - 5

Edited by WombatBreath
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Well I am pretty sure that E is the 5th letter but I am failing at proving the logic behind it at the minute :dry:

This probably wouldn't be accepted because it is a little vague but;

The only letter that TEEPEE, CLOSER and WALLET share is the E at the 5th spot. So it almost definitly has to be there but I can't prove why it can not be there. I am just going to be quiet now - my attempt at analysis is digging me into a whole :P

Edited by mEEster-Michael
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Couldn't edit my earlier post, hence it still says whole and not hole :/ haha

I meant to guess TURNER but forgot.

If 3 are correct then I would say that T is first because of TEEPEE having 2 correct, so T in first place. The E would be 5th because of WALLET, TEEPEE and CLOSER all having an E there, and then because CLOSER also has 2 correct I would take the R from that as being the 6th letter because....(INSERT LOGIC HERE).... and that is why I have guessed TURNER! hehe

Edited by mEEster-Michael
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CLOSET - if 1 then ?????R is proven - only diff from CLOSER-2- if 3 then ?????T is proven - same reason

??????TEEPEE - 2EASELS - 0SCHIST - 0CLOSER - 2WALLET - 1 LETTER - 1TURNER - 1CLOSET - 1The E logic was still a bit vague because there could be other letters that could not be similar and yet have the score 1 or more.

what about my logic ?? :-s .. if CLOSER - 2 and CLOSET - 1 the R is proven ?!

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As Yodell's and benjer3's logic is sound above and thus ??EP?R proven

lettEr=1 (for R) and eAsels=0 means only the W of wallet remains to score so actually W?EP?R is now proven,

so...

...hmm don't have any words that fit and neither does onelook.com

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WALLOP ?

If WALLOP=0 then ????E? is proven.

CLOSER=CLOSET=2 means that neither R nor T can be the last letter.

WALLET=1 and so WALLE_=1 since the T can't score

WALL__ is common and WALLOP=0 so ____E_=1

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