[Guest]

If you are unfamiliar with Kakuro, check out http://en.wikipedia.org/wiki/Kakuro

I've attached the puzzle.

The rules are the same as traditional Kakuro, the only difference being

that instead of numbers, the letters A-J are present, each representing

a different digit from 0-9.

Just determine which letter corresponds to which number.

[Guest]

I enjoy Kakuro, so this one was fun. It helps if you've done a lot of this puzzles and know some of the patterns.

A-9

B-2

C-4

D-3

E-1

F-7

G-5

H-6

I-8

J-0

[Guest]

Since CG must be all numbers 1-9, C=4 and G=5. Sum of 1-9 is 45.

Since J is not included it must be 0

EE must be something that has a 4 digit sum and a 2 digit sum. 11 is the only number that works for that. E=1

BJ must have 3 digit and a 4 digit sum. Since 1 is taken 2 is the only option. B=2

Since you can't have any double digit sums higher than 45 and 4 is taken, D=3

H must be something that when two other numbers are added to it equal a one digit number (A). 6 is the only option left. H=6

A must be 6 plus two other numbers. A=9

EF can only be 17 or 18, since it is the sum of two digits it must be 17. F=7

I=8 by elimination.

[Guest]

I love Kakuro (Cross sums to those of us that have been working them for years) so when I saw your puzzle, I had to have a crack at it.

J=0

E=1

B=2

D=3

C=4

G=5

H=6

F=7

I=8

A=9

And my method for solving....

CG = all the numbers so CG must be 45.

C=4, G=5

J isn't in the list of numbers in the middle so J must = 0

2 numbers at the bottom left going down = EE. 11 is the only # small enough to work so E=1.

F = 3 unique numbers so F must be >= 6 and A = F+2 other numbers. A must be 9 = F+1+2 so A=9 and F=6.

Upper left B0 = 1 + 3 numbers. 20 is the only number that works so B=2.

DJ right above BJ = 4 numbers so D must = 3

That only leaves F & I unsolved for 7 & 8. Lower right corner EF = 2 numbers. It can't be 18 so F must = 7 and that leaves I=8.

Now I can peek at Ismithers answer.