bonanova 81 Report post Posted March 7, 2008 Four basic numbers from science and mathematics have the symbols pi, e, 1 and i. Their values are pi = 3.1415926536 ... e = 2.718281828459 ... 1 = unity i = sqrt[-1] Arrange these numbers, using them once and only once, so that they equal 0 using only the operations +, ×, and exponentiation. Use the spoiler, Luke. Share this post Link to post Share on other sites
0 Guest Report post Posted March 7, 2008 e^(i(pi)) + 1 = 0 Share this post Link to post Share on other sites
0 Guest Report post Posted March 7, 2008 Four basic numbers from science and mathematics have the symbols pi, e, 1 and i. Their values are pi = 3.1415926536 ... e = 2.718281828459 ... 1 = unity i = sqrt[-1] Arrange these numbers, using them once and only once, so that they equal 0 using only the operations +, ×, and exponentiation. Use the spoiler, Luke. Are we allowed to use functions ... like ceiling, floor, Int()?? pi*(1+i^floor(e))=0 ^ used for exponentiation Share this post Link to post Share on other sites
0 bonanova 81 Report post Posted March 7, 2008 Are we allowed to use functions ... like ceiling, floor, Int()?? Sorry ... just the ones listed. Share this post Link to post Share on other sites
0 Guest Report post Posted March 7, 2008 1+e^(i*PI)=1+cos(PI)+i(sin(PI)) ... in trigonometric form which is equal to zero. Share this post Link to post Share on other sites
0 unreality 1 Report post Posted March 7, 2008 use Euler's identity, which is the special case of Euler's formula, the equation for going around a circle with a real x axis and a nonreal y axis the special case is: epi*i + 1 = 0 which comes from this: epi*i = -1 which comes from this: etheta*i = cos(theta) + i*sin(theta) Share this post Link to post Share on other sites
Four basic numbers from science and mathematics have the symbols pi, e, 1 and i.
Their values are
pi = 3.1415926536 ...
e = 2.718281828459 ...
1 = unity
i = sqrt[-1]
Arrange these numbers, using them once and only once, so that they equal 0
using only the operations +, ×, and exponentiation.
Use the spoiler, Luke.
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