[bonanova 76]

Four basic numbers from science and mathematics have the symbols pi, e, 1 and i.

Their values are

pi = 3.1415926536 ...

e = 2.718281828459 ...

1 = unity

i = sqrt[-1]

Arrange these numbers, using them once and only once, so that they equal 0

using only the operations +, ×, and exponentiation.

Use the spoiler, Luke.

[Guest]

e^(i(pi)) + 1 = 0

[Guest]

Four basic numbers from science and mathematics have the symbols pi, e, 1 and i.

Their values are

pi = 3.1415926536 ...

e = 2.718281828459 ...

1 = unity

i = sqrt[-1]

Arrange these numbers, using them once and only once, so that they equal 0

using only the operations +, ×, and exponentiation.

Use the spoiler, Luke.

Are we allowed to use functions ... like ceiling, floor, Int()??

pi*(1+i^floor(e))=0

^ used for exponentiation

[bonanova 76]

Are we allowed to use functions ... like ceiling, floor, Int()??

Sorry ... just the ones listed.

[Guest]

1+e^(i*PI)=1+cos(PI)+i(sin(PI)) ... in trigonometric form

which is equal to zero.

[unreality 1]

use Euler's identity, which is the special case of Euler's formula, the equation for going around a circle with a real x axis and a nonreal y axis

the special case is:

e^pi*i + 1 = 0

which comes from this:

e^pi*i = -1

which comes from this:

e^theta*i = cos(theta) + i*sin(theta)