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Each of three circles passes through the centers of the other two.

The area interior to all three is quite close to, but different from, one quarter of the area A of a circle.

post-1048-022094500 1288317681.gif

Can you determine, through inference, construction or calculation, whether it's smaller or larger than A/4?


Arrgh. Forgot that I posted this problem before;* where it was solved by calculation.

I'll bend the Den's rules a bit and leave it up, but modified.

Please provide a purely geometrical solution.

*A benefit of advancing age is the ability to hide one's own Easter eggs. :blush:

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Less than 1/4.

The ratio could be calculated as

M = [3(/pi/6 R^2 -S) + S]/[(/pi) R^2]

where S = /sqrt(3) R^2 /4 is the area of the triangle

M = 1/2 - 2S/[(/pi) R^2]

= 1/2 - /sqrt(3) /(2/pi)

< 1/4

As /sqrt(3) >1.6 > 1/4 (2/pi)

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Don't know how to draw but hope it's understandable:

Let the center of the circles be A, B, C respectively and denote the intersecting point of circles A and B as M, that of A and C as N.

Consider the the area of AMB and ANC, together they make 2S. MAN is a straight line and is the diameter of circle A. Move the parts of AMB and ANC which are outside of the half circle MANCB and paste it to BC, there's still a blank space in the half circle.

Thus 2S < area of the half circle.

S< 1/4 area of the circle.

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Please provide a purely geometrical solution.

Nice Easter Egg indeed :)

Completing the picture with four more circles:

post-36575-045535500 1288322270.png

So 1/4 of a circle is one blue + one red petal + one half blue + one half red petal

And the area in question is one blue + one red petal + one red petal.

We need to if either blue or red is the biggest. If red is biggest than Area >1/4 CircleArea, else Area <1/4 CircleArea.

Construct another circle below to get a red petal inside the blue area. So 1/4 CircleArea > Area.

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I used the area of a triangle (as an equilateral triangle with each leg being r, using Pythagorean theorem I got (r^2 sqrt(3))/4 , area of the circle (A = pi * r^2) and area of an arc segment (60' angle so 1/6*A) to get 1/2A - r^2*sqrt(3), which I don't know if it is bigger or smaller than 1/4A !!! I think it isn't...

*edit: Maybe I was calculating too much and missed the point... I looked at the spoiler above this and saw pictures...

back to the drawing board

Edited by Asitaka
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