superprismatic Posted September 8, 2010 Report Share Posted September 8, 2010 Divvy up the following numbers into 10 different groups such that each group sums to 25: 1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3, 3,3,4,4,4,4,4,5,5,5,5,6,6,6,7,8,8, 8,9,9,9,10,13,14,15,20,21 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 8, 2010 Report Share Posted September 8, 2010 21 4 20 5 15 6 4 14 4 4 3 10 5 5 2 3 13 3 3 2 4 9 9 7 8 9 8 6 6 5 8 1 1 1 1 2 2 2 2 2 2 3 3 3 Divvy up the following numbers into 10 different groups such that each group sums to 25: 1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3, 3,3,4,4,4,4,4,5,5,5,5,6,6,6,7,8,8, 8,9,9,9,10,13,14,15,20,21 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 8, 2010 Report Share Posted September 8, 2010 1-21,4 2-20,5 3-15,10 4-14,9,2 5-13,9,3 6-9,8,8 7-8,7,6,4 8-6,6,5,5,3 9-5,4,4,4,3,3,2 10-3,3,3,2,2,2,2,2,2,1,1,1,1 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 8, 2010 Report Share Posted September 8, 2010 We should add a couple twists to this puzzle: 1) How many different unique solutions exist? 2) Can you determine a set of positive integer numbers that makes a unique solution? If not, what is the minimum sum required to form a unique solutions (i.e. all add to 50 instead of 25). Quote Link to comment Share on other sites More sharing options...
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superprismatic
Divvy up the following numbers into
10 different groups such that each
group sums to 25:
1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3,
3,3,4,4,4,4,4,5,5,5,5,6,6,6,7,8,8,
8,9,9,9,10,13,14,15,20,21
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