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Rollo


unreality
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STANK

If 4, then _P_ _K is right. S, A already proved from SMACK, leaving _M_CK = 1. If M is correct, then the K is wrong. If STANK is 4, _T_NK = 2 and T and N must be right, but T and M collide, so M is wrong.

If C is right, then K is wrong. If STANK = 4, then _T_NK = 2. Since C is right, N is wrong and T and K must be right. This is a contradiction, so C is wrong. Therefore K is right in SMACK.

Since K is right, C is wrong in _M_CK, so P must be right in SPACE = 3 since the S and A are prove and C is wrong. The E is wrong from SPACE and SPACY having the same value, so neither E nor Y is right.

Too slow... :(

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SPANK

EXIST - 0

CRABS - 1

BROAD - 0

SLOBS - 1

CLIMB - 0

CRAPS - 1 

BLIPS - 0

FOALS - 1

CROPS - 0

SPACY - 3

SPACE - 3

SMACK - 3

STANG - 3

dawh +10

quag + 20

maurice +13

maurice - 1141

Glycereine - 966

plainglazed - 924

Maquis - 608

Cherry Lane - 532

araver - 521

Vineetrika - 469

Izzy - 386

Unreality - 289

dawh - 260

t8t8t8 - 190

NickFleming- 180

Framm - 177

golfjunkie - 170

quag - 148

woon - 141

Fabpig - 116

JarZe - 96

Blablah99 - 89

Harvey45 - 77

MollyMae - 46

Hirkala - 36

yuiop - 21

Abhisk - 20

PVRoot - 20

Filly - 19

Prince Marth - 15

DudleyDude - 15

phaze - 15

Kac_cotu - 5

Panther - 5

and great proof dawh, I didn't see quag's response until I saw your last line

Edited by maurice
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ROUND -

if 1 then R is first as FOUND = 0 rules out _OUND

if 0 then E is second as REPLY = 1, ROUND = 0 rules out R and APPLY = 0 rules out _ _ PLY.

Edited by maurice
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