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Rollo


unreality
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_ _ _ _ _


ELVES 0

GEESE 1

That's a bit faster start than the previous round... :rolleyes:

Unfortunately, I foolishly won the previous round and decided to host this despite the fact that I'm leaving soon and won't be back for a couple hours at best. :duh:

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has there been a consensus yet on whether to accept the kinds of conditional statements that nickfleming is saying?

I think we've been allowing them, but for one word max. Like, I can't post a stream of words and logic between them (as with Nick's gnoll and knoll), but if GNOLL has already been scored as 1, and someone posts KNOLL and says "If it's 0, then the G in Gnoll must be right because the first letter is the only thing to change", it's okay.

Edited by Izzy
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Adding Nick's incorrect logic for the previous ROLLO hosted by me


Izzy - 356

Unreality - 279

Glycereine – 219

Plainglazed - 185

Framm - 177

t8t8t8 - 163

Vineetrika - 117

Dawh - 81

golfjunkie - 72

woon - 63

NickFleming-54

blahblah99 - 28

yuiop - 21

Abhisk - 20

PVRoot - 20

JarZe - 20

Prince Marth - 15

DudleyDude - 15

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Sorry haven't played long. I don't know where the rules have been changed. As long as you didnt give points to me :thumbsup: Any other updates to rules I should know about? And go GNOME!!And no, I'm not mistakenly reposting the answer, I'm just hoping its right :D

Edited by NickFleming
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G R O U T


ELVES 0

GEESE 1

PEEVE 0

GNOLL 2

KNOLL 1

BUGGY 0

GNOME 2

TOLLS 0

GROWN 3

GROVE 3

GROUT 5

Glycereine +30 dawh +11

Izzy - 356

Unreality - 279

Glycereine – 249

Plainglazed - 185

Framm - 177

t8t8t8 - 163

Vineetrika - 117

Dawh - 92

golfjunkie - 72

woon - 63

NickFleming-54

blahblah99 - 28

yuiop - 21

Abhisk - 20

PVRoot - 20

JarZe - 20

Prince Marth - 15

DudleyDude - 15

Good job glycereine! :thumbsup:

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Geese tells us e isn't the last letter. This gives us _NOM_ from gnome for 1 point, and _ROWN from grown for 2.

Knoll = 1, and tolls = 0, so the possible right letters are _NO_L. One of these is correct.

_NOM_ - 1

_ROWN - 2

_NO_L - 1

If N from NOM, then it can't be the R or O from ROWN, leaving the WN. (GN_WN)

If the O, then we have combinations of RO, OW, O_N (GRO_ _, G_OW_, G_O_N)

If M, then, RO, RN, ON (GROM_, GR_MN, G_OMN)

GN_WN satisfies _NO_L = 1, but there's no letter than can be plugged in to make a legit English word.

GRO_O, G_OW_, and G_O_N all satisfy that _NO_L = 1, and would make o the third letter, same with GROM_ and G_OMN.

Gr_mn is our only possibly word where o isn't the third letter, but again, there is no real English word that satisfies those letters.

So, by process of elimination, o must be the third letter. This means that N cannot be the second letter and L cannot be the last letter.

(And.. yeah, I just realized Glyc posted a much easier way to prove the same thing, so let's hope Grove doesn't equal three. :P)

*edit* Pssh, never mind. Too slow. >_>

Edited by Izzy
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