Jump to content
BrainDen.com - Brain Teasers
  • 0
Sign in to follow this  
Guest

Question

Guest

Lets say that on a clock, y is the distance from the 12:00 to the minute hand (clockwise) and z is the distance from 12:00 to the hour hand. What time between 3-4 is y two times as much as z?

Share this post


Link to post
Share on other sites

5 answers to this question

  • 0
Guest

Say the minute hand (Y) and the hour hand (Z) are both on 12:00. That would make Y=0 and Z=0, leaving the second hand to pass between 3 and 4 (it's not specified that the minute hand or the hour hand, themselves, had to be between 3 and 4). If Y=0 and Z=0, then 2(Y) also = 0, so 2(Y)=Z.

I guess that's kinda cheating, but it's all I got.

Share this post


Link to post
Share on other sites
  • 0
Guest
Say the minute hand (Y) and the hour hand (Z) are both on 12:00. That would make Y=0 and Z=0, leaving the second hand to pass between 3 and 4 (it's not specified that the minute hand or the hour hand, themselves, had to be between 3 and 4). If Y=0 and Z=0, then 2(Y) also = 0, so 2(Y)=Z.

I guess that's kinda cheating, but it's all I got.

I guess I was a bit unclear. The time has to be between 3:00 and 4:00

Spoiler for hint:

it is around 3:30
Edited by HRAEDIUS

Share this post


Link to post
Share on other sites
  • 0
Guest

About 3:34

2z=y

z-15=60/y

solving for y from the two equations, y=33.6 (34 rounding to the nearest integer)

Share this post


Link to post
Share on other sites
  • 0
Guest

I know where I made a mistake.

3:36

2z=y

(z-15)/5=y/60

solving for y from the two equations, y=36 and z=18

Hope this one makes sense.

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

Sign in to follow this  

  • Recently Browsing   0 members

    No registered users viewing this page.

×