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Lets say that on a clock, y is the distance from the 12:00 to the minute hand (clockwise) and z is the distance from 12:00 to the hour hand. What time between 3-4 is y two times as much as z?

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Posted · Report post

Say the minute hand (Y) and the hour hand (Z) are both on 12:00. That would make Y=0 and Z=0, leaving the second hand to pass between 3 and 4 (it's not specified that the minute hand or the hour hand, themselves, had to be between 3 and 4). If Y=0 and Z=0, then 2(Y) also = 0, so 2(Y)=Z.

I guess that's kinda cheating, but it's all I got.

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Posted (edited) · Report post

Say the minute hand (Y) and the hour hand (Z) are both on 12:00. That would make Y=0 and Z=0, leaving the second hand to pass between 3 and 4 (it's not specified that the minute hand or the hour hand, themselves, had to be between 3 and 4). If Y=0 and Z=0, then 2(Y) also = 0, so 2(Y)=Z.

I guess that's kinda cheating, but it's all I got.

I guess I was a bit unclear. The time has to be between 3:00 and 4:00

Spoiler for hint:

it is around 3:30
Edited by HRAEDIUS
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Posted · Report post

About 3:34

2z=y

z-15=60/y

solving for y from the two equations, y=33.6 (34 rounding to the nearest integer)

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Posted (edited) · Report post

close but a bit off

Edited by HRAEDIUS
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Posted · Report post

I know where I made a mistake.

3:36

2z=y

(z-15)/5=y/60

solving for y from the two equations, y=36 and z=18

Hope this one makes sense.

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