[Guest]

you have three dice. on dice 1, you have red on 5,2; blue on 6,1; yellow on 4,3.

on dice 2, you have blue on 5,2; yellow on 6,1; red on 4,3.

on dice 3, you have yellow on 5,2; red on 6,1; blue on 4,3.

what are the chances of getting a "straight flush"? (three dice of the same color in sequence.)

[Guest]

If you are looking for this kind of sequence 1,2,3 ;|difference|=1 like in poker straight flush

4R 5R 6R

1R 2R 3R and the same sequences for the other two colors

P=2*3/6³~2.78%

[plainglazed]

the total number of combinations is 18C3=816. then the number of straight flushes would be 4C1*3C1=12. four possible straights: (1,2,3) (2,3,4) (3,4,5) (4,5,6) in each of the three different colors. so the odds would be 12/816 or 1.47% ?

[plainglazed]

total number of combinations would be 6C1*6C1*6C1 or 216 like det said; so 12/216 or ~5.56%

[Guest]

1/36

The odds of getting all red = 1/3 X 1/3 X 1/3 = 1/27

If all do turn up as reds, there are only 2 possible sequences 123 and 456 and 8 possible combinaions

So, odds of them being a sequence: 2/8 = 1/4

Odds of being a red straight flush : 1/27 X 1/4

Odds of any straight flush = 1/27 X 1/4 X 3 = 1/36

Edited April 11, 2010 by HB921

[plainglazed]

when in doubt, stick with det. see the errors of my ways now.

[Guest]

1/36. here's why.

for the first dice, no matter what you get, you still have chance equal chance of getting straight flush.

for the remaining two dice, you need a specific number and color. (1/6 chance on each). thus 1/36.

[Guest]

1/27

[peace*out]

1/27th right? ... all 3 dice have a 1/3rd probability. so if you have 1/3rd on one dice, and 1/3 probability of the other dice, than 1/3 * 1/3 *1/3 is 1/27!!!!!

so yah: 1/27th

[Guest]

1/27th right? ... all 3 dice have a 1/3rd probability. so if you have 1/3rd on one dice, and 1/3 probability of the other dice, than 1/3 * 1/3 *1/3 is 1/27!!!!!

so yah: 1/27th

Problem is already solved, check the previous posts for the correct answer.