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1996 - Back to the Number Puzzles

Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:

29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.

All the numerals must be used in the given order (each just once) and without turning upside down.

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1996 - solution

post-2-1175278139_thumbgif

I used [brackets] as the symbol for root.

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  • 3 months later...

I get all of them except the answer 29... please explain. It would end up being -1+3 + (3^6) which is 2 + 729 = 731 The only way it would work if is 2 is added to 27. To get 27 the multiples are 3x3x3 and I can't figure that out with 9 and 6.

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I get all of them except the answer 29... please explain. It would end up being -1+3 + (3^6) which is 2 + 729 = 731 The only way it would work if is 2 is added to 27. To get 27 the multiples are 3x3x3 and I can't figure that out with 9 and 6.

You forgot a root:

-1 + root(9) + root[root(9)^6]

=-1 + 3 + root[3^6]

=-1 + 3 + 3^3

=-1 + 3 + 27

=29

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  • 8 months later...

1996 - Back to the Number Puzzles

Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:

29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.

All the numerals must be used in the given order (each just once) and without turning upside down.

For 32 there is another way to do it:

-1+[9]x9+6=32

For 38:

19/[9]/6=19x6/[9]=38,

actualy is the same,just 1 step before the shown equation.

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  • 9 months later...
1996 - Back to the Number Puzzles

Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:

29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.

All the numerals must be used in the given order (each just once) and without turning upside down.

1996 - solution

post-2-1175278139_thumbgif

I used [brackets] as the symbol for root.

another solution for 76:

91 - (9+6) = 76

91 - 15

and for 35:

[[9]6] + 9 - 1 = 35

[3^6] + 9 - 1

3^3 + 9 - 1

27 + 9 - 1 = 35

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  • 1 month later...
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