k-man
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Everything posted by k-man
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I think it means that every number of handshakes possible given the number of people was performed. Somebody did 0 handshakes, somebody did 1, etc up to 6, which is the maximum possible # of handshakes given the rules of the puzzle. Based on this understanding I believe amitgols got the correct answer in post #8. Please use spoilers, amitgols, and welcome to the den!
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Looked at Mukul Verma's solution and he is right. My answer is wrong. Good job Mukul!
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Thanks, Nana.
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Good post, swongy, and welcome to the den. Please use spoilers in the future. I also noticed a weakness in this puzzle after the correct answer was posted. If this was a pickling factory, the visitors must have known that and wouldn't expect the vinegar to "instantly dissolve" Jodi.
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I don't really see a greater challenge in this.
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Just saw this, so without doing any math here is the answer to the intuitive question
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HoustonHokie and bonanova got it! Extra credit to bona for the exact formula!
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There is a unit square on a plane. A unit circle (r=1) is placed randomly, so that its center is somewhere inside the unit square. Every point inside the unit square has the same probability of being chosen as the center of the unit circle. What is the probability that the square fits entirely inside the circle?
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Is the left arm a whole number of times longer than the right arm?
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Wolfgang, can you explain how you came up with this answer? By your definition, the day is the time the planet rotates around its own axis. Given that the angular speed is the same, the length of the day on all three planets must be the same - it takes the same amount of time to rotate 360 degrees. Also, by your definition, a year is 365 days, so where does this difference in ages come from?
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That's an interesting approach with the complex numbers, but it's more applicable to the original problem as it doesn't take into account that every step is 1/2 the distance of the previous step. BTW, I still haven't solved this problem myself, so any new thoughts and ideas are welcome. I did create a simulation of the problem and after 100 million tries the result is that the probability of the ant escaping is
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This is a new twist to the original puzzle posted by magician. An ant is in the center of a circle (diameter 3m). He walks in a straight line in a random direction for 1m. He's getting tired, so his next move is again in the random direction, but only for 0.5m. Every subsequent move is 1/2 of the previous move in length and in a random direction. If the ant moved in the same direction twice he would escape the circle in just 2 moves (let's consider reaching the edge of the circle as escape). But, if any of his moves are in the opposite direction of the previous move he will never reach the edge. So, here is the question... What's the probability of the ant escaping the circle?
