phaze
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Posts posted by phaze
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9 hours ago, BMAD said:
The second half of the solution seems to be inefficient though. Once we stop at hole 4 and conclude that the fox is in fact at an even hole the only hole left is hole number 2 which means that we don't need to start all over. Simply inspecting three and then two would be enough to find the fox.
Exception which means it could be 4
check hole 2 fox is in 5
check hole 3 fox is in 4
check hole 4 fox is in 3
check hole 2 fox is back in 4
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still not sure of the exact number but I believe it is "a prime one"
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5 hours ago, plainglazed said:
so does the (retired) mean this was a race to 300? if not...
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On 16/01/2017 at 8:20 AM, phaze said:After this round as host I am going to have to retire from ROLLO. I have developed a spreadsheet you see which tells me the remaining words that are allowable and the letter/letters that will be most likely for the next word. Given this obvious advantage I cannot in good conscience continue.
@planglazed would you like a spreadsheet or would you like to see me (almost on my own) guess your word in around 10 guesses or less(again)?
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FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
PRONE - 1
BLIND - 1
STUNG - 0
STONE - 1 : 5 points Araver
BLAND -1
BRAND -1
STATE - 1: 5 points Miss Kitten
BINGE - 3
BULGE - 2
BIBLE - 5 - 20 point Plain-Glazed
phaze - 288 + 15 = 303 (retired)
maurice - 266
plainglazed - 236 + 20 = 256
araver - 152 + 5 = 157
Logophobic - 143
nana - 10
Miss Kitten - 0 + 5 = 5 -
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
PRONE - 1
BLIND - 1
STUNG - 0
STONE - 1 : 5 points Araver
BLAND -1
BRAND -1
STATE - 1: 5 points Miss Kitten
BINGE - 3
BULGE - 2
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Notes that may help someone
* there are 12 different keys in the foreground
* there are 16 cogs on the tree
* there are 3 different colours for branches on the cog tree
* there are 4 real cogs (with a number of sub-cogs)
* there are 4 cog shadows
* the bottom most shadow appears to be a shadow of the real cog next to it
* the upper two shadow cogs mirror the lowest cog (folding the picture frame into quarters would allow them to overlap)
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B _ _ _ E
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
PRONE - 1
BLIND - 1
STUNG - 0
STONE - 1 : 5 points Araver
BLAND -1
BRAND -1
STATE - 1: 5 points Miss Kitten
BINGE - 3
3 possible words left
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There is only 6 words that is could possibly be
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B _ _ _ E
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
PRONE - 1
BLIND - 1
STUNG - 0
STONE - 1 : 5 points Araver
BLAND -1
BRAND -1
STATE - 1: 5 points Miss Kitten
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_ _ _ _ E
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
PRONE - 1
BLIND - 1
STUNG - 0
STONE - 1 : 5 points Araver
BLAND -1
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_ _ _ _ E
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
PRONE - 1
BLIND - 1
STUNG - 0
STONE - 1 : 5 points Araver
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_ _ _ _ _
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
PRONE - 1
BLIND - 1
STUNG - 0
Lucky I can remember what the original word is.
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_ _ _ _ _
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
PRONE - 1
BLIND - 1
2 more guess, you could always get lucky but the next 2 words the spreadsheet recommends are not the correct one
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"Steve" asked me to follow him. Either he reasoned that it was expedient to go near the beast or meeting it was as much of a surprise to him as it was to me. I don't see the relevance of your question to the crime I am accused of, unless you have already acknowledged the shark presence and thus found me not guilty.
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_ _ _ _ _
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
EERIE - 1
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My spreadsheet can figure it out in approx 5 more guesses. 10 bonus points if you can guess the word in 5 or less guesses
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_ _ _ _ _
FROST - 0
TARES - 0
HOSTS - 0
GAMES - 0
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There is only one answer when you take into account that certain numbers need to be opposite each other
The way I worked it out was by observing that the dice has landed each time on a different axis, If it had been the same axis at least 2 of the sides (total - front & top) would have been the same value. I then did a brute force by assuming first that the third throws top and front was 1,5 and then 2,4. This would mean that the sides for the first two throws would both need to include either 1 or 5, or 2 or 4. also means that we can eliminate (1,15 and 5,11) or (2,14 and 4,12) from the third throw. From there it is reasonably easy to prove that the third throw cannot be (1,5) on the top & face. (2,4) on the top & face. is a little more tricky and I would suggest drawing a cube with possible values on each respective face. In the end I found that only Writersblock's answer existed.
An interesting follow up question would be if Morty cheated by switching dice between 3 dice with the same numbers (2,4,5,7,8,11) but different configurations could he ensure that there would be no possible solution no matter which way the dice landed on each throw?
NOTE I haven't personally figured this out yet
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OK go
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PS: TARES is a good word to start with (Or I could be leading you astray)
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Then it must be UNION
That or ANION
After this round as host I am going to have to retire from ROLLO. I have developed a spreadsheet you see which tells me the remaining words that are allowable and the letter/letters that will be most likely for the next word. Given this obvious advantage I cannot in good conscience continue.
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If PUSHY is 0 try ONION
if ONION is 1 go for RHINO
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PUSHY
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LOGIC
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