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Posts posted by jasen


each number must be an unique number or not?

using computer program that check your solution.
you input your answer to the computer secretly,
then the computer check it and say right or wrong. 
Suppose the leading bullet has 1/k chance of being the fastest. Then we will not get complete annihilation.
So far, so good. ....After rethinking this, I understand the doubter opinion.
We have to avoid using "first bullet fastest"
Although first bullet is not the fastest, it it still possible that the first bullet escape1 4 2 3 > in this arrangement 3 (first bullet) is not the fastest, but it escape.

we better explain it in another way.
with n bullets, if the fastest bullet is not the first, there is (n1)/n cases that we are sure there will be a collision. n2 bullets will remains. an so on...

Mentally draw a line that connects the horns of a crescent moon and then extend this line down to the horizon. ........
Taken from: http://www.naturalnavigator.com/findyourwayusing/moon
OK, if there is crescent moon outside, this is one of the answers.

The interesting fact is : Whatever number of bullets fired, the highest probability is 2 bullets left.
initial 2 bullets 1000000 tries
P of 0 bullets anhilated = .500683
P of 2 bullets anhilated = .499317initial 4 bullets 1000000 tries
P of 0 bullets anhilated = .041601
P of 2 bullets anhilated = .582647
P of 4 bullets anhilated = .375752initial 6 bullets 1000000 tries
P of 0 bullets anhilated = .001354
P of 2 bullets anhilated = .076568
P of 4 bullets anhilated = .609111
P of 6 bullets anhilated = .312967initial 8 bullets 1000000 tries
P of 0 bullets anhilated = .000029
P of 2 bullets anhilated = .00346
P of 4 bullets anhilated = .104317
P of 6 bullets anhilated = .619309
P of 8 bullets anhilated = .272885initial 10 bullets 1000000 tries
P of 0 bullets anhilated = 0
P of 2 bullets anhilated = .000075
P of 4 bullets anhilated = .006025
P of 6 bullets anhilated = .127299
P of 8 bullets anhilated = .620703
P of 10 bullets anhilated = .245898initial 12 bullets 1000000 tries
P of 0 bullets anhilated = 0
P of 2 bullets anhilated = .000002
P of 4 bullets anhilated = .000186
P of 6 bullets anhilated = .008569
P of 8 bullets anhilated = .147078
P of 10 bullets anhilated = .618606
P of 12 bullets anhilated = .225559initial 14 bullets 1000000 tries
P of 0 bullets anhilated = 0
P of 2 bullets anhilated = 0
P of 4 bullets anhilated = .000002
P of 6 bullets anhilated = .000258
P of 8 bullets anhilated = .011055
P of 10 bullets anhilated = .164173
P of 12 bullets anhilated = .614903
P of 14 bullets anhilated = .209609initial 16 bullets 1000000 tries
P of 0 bullets anhilated = 0
P of 2 bullets anhilated = 0
P of 4 bullets anhilated = 0
P of 6 bullets anhilated = .000008
P of 8 bullets anhilated = .000366
P of 10 bullets anhilated = .013871
P of 12 bullets anhilated = .178564
P of 14 bullets anhilated = .610811
P of 16 bullets anhilated = .19638initial 18 bullets 1000000 tries
P of 0 bullets anhilated = 0
P of 2 bullets anhilated = 0
P of 4 bullets anhilated = 0
P of 6 bullets anhilated = 0
P of 8 bullets anhilated = .000005
P of 10 bullets anhilated = .000545
P of 12 bullets anhilated = .016474
P of 14 bullets anhilated = .191395
P of 16 bullets anhilated = .606078
P of 18 bullets anhilated = .185503initial 20 bullets 1000000 tries
P of 0 bullets anhilated = 0
P of 2 bullets anhilated = 0
P of 4 bullets anhilated = 0
P of 6 bullets anhilated = 0
P of 8 bullets anhilated = .000001
P of 10 bullets anhilated = .000012
P of 12 bullets anhilated = .000665
P of 14 bullets anhilated = .018998
P of 16 bullets anhilated = .203064
P of 18 bullets anhilated = .601149
P of 20 bullets anhilated = .176111 
Of cards  Uncover the three next elements of the following sequence: 8593,8600,8593,8592,8599,...
8593, 8600, 8593, 8592, 8599, 8593, 8591, 8598

1111111110000
since 720 * 1543209875 = 1111111110000

Hidden Content
Hidden Content
Right !
You can create a compass from a battery, copper coil, a nail, and thread.
1. take a battery, and coils from the clock.
2. take a nail from wall. (to hang a clock, we need a nail).
3. get thread from your cloth.
4. create magnet. http://www.wikihow.com/CreateaMagnetWithaWireandaNail
5. using right hand rule to find south and east. https://en.wikipedia.org/wiki/Righthand_rule
6. Find center ballance, and hang the magnet using thread.now you know direction.

sorry, wrong thread.

Hidden Content
Right
You can create a compass from a battery, copper coil, a nail, and thread.
1. take a battery, and coils from the clock.
2. take a nail from wall. (to hang a clock, we need a nail).
3. get thread from your cloth.
4. create magnet. http://www.wikihow.com/CreateaMagnetWithaWireandaNail
5. using right hand rule to find south and north. https://en.wikipedia.org/wiki/Righthand_rule
6. Find center ballance, and hang the magnet using thread.now you know direction.

1110101111010000
since 1110101111010000 / 720 = 1541807098625

Doesnt Sun consider as a star?
Well, it's nighttime, so you shouldn't see the Sun.
The Sun is a star indeed, and it didn't occur to me the moon is not a star. Supposedly you could deduce the cardinals from the hour and the moon position?In the night you can't use sun as guidance.
Unfortunately no astronomer between the prisoners,
nobody could deduce the cardinals from the hour and the moon position.
You see arround, wheather there are tools you can use.
But you only can find electric lamp, hanging photo, and the working clock.1st clue : use component from the clock.

First player will always choose a biggest number and put () in front
Second player will always choose a biggest number and put (+) in frontso the result will be
20+1918+1716+1514+1312+1110+98+76+54+32+1 = 10

you are a prisoner in a huge jail. All prisoner will be executed in the morning next day. Fortunately No guard there. Suddenly in midnight a prisoner can break his cell. and take all keys. But he will not free and let others escape with him, except there is someone can tell directions (south, east, north or west), because wrong directions means recaptured. Nobody can read star for directions. You see a clock on the wall ticking, and your execution time get closer.
What should you do to know the right direction?

Should be:
Hidden Content
This is a subject in cryptography
A don't want to send his key to B.
B also don't want to send his key to A.
But they want to communicate in insecure Internet connection.
So they have to use an encryption method which work like this.
Only commutative encryption method can answer this problem. 
P(1 Black) = 0.99 ^{100 }
P(2 Black) = 0.98 ^{100}
P(3 Black) = 0.97 ^{100 }
P(4 Black) = 0.96 ^{100}
P(5 Black) = 0.95 ^{100 }
.
.
P(99 Black) = 0.01 ^{100 } +
P(with 1 or some black) = 0.572....
P (all white) = 1
P (all white) : P(some black) = 1 : 0.572Conclusion : do not take the bet !!


I have a solution it can be really stright, not just by add S in front

fore case 2, I have run a computer simulation, which show that you should not bet.
The probability that all white is only .63
so the quite fair bet is 2:1 not 5:1

There are 2 cases
case 1. Someone want to fool you, he just put one black
case 2. Nobody try to fool, maybe there are no black,1 or more than one black.in case 1 :
you should not take the bet.
there is 35% probability that in 100 tries you cannot find the black one.in case 2 :
I still confuse how to solve this case. 
Yes, I can agree with that logic. Thanks.
In creating a question in An IQ test, the creator must make sure that there is no double interpreatation to the question (the question can be answered differently)
example if you ask :
1,2,....a. 3
b. 4
c. 5this is a bad question,
because there is a double interpretation thereyou usually answer a.3
but b.4 is also correct, because : 2^{0} = 1, 2^{1} = 2, 2^{2} = 4so to avoid this, one of the correct answer must be removed from the question.

in the question above you may think the logic that I over is questionable.
But it also acceptable, so if the question maker do not allow my logic, so he must
prevent this kind of logic appear, so he must create another option that is also not a duplicate.but since my logic, and pavan logic come to one option, so this is still acceptable.
So, if we have found a logic in an IQ test question, just use it.

No, You can be deceived, if there is just 1 black,2 blacks or even 10 blacks marble there, and you are unlucky to find the black marble.

I think:
Hidden Content
Right answer, but I'm sure some of us still wonder why.
Let's cek the combinations
note (x,y) means : bullet at x^{th} hole in gun1 and bullet at y^{th }hole in gun2
since gun1 is shot 1st so if x<= y then means 1st player win.
so (1,1) or (2,2) means 1^{st} player win.for 2 holes and 1 hole guns
(1,1) 1st win
(2,1) 2nd winfor 3 holes and 2 holes guns
(1,1) 1st win (1,2) 1st win
(2,1) 2nd win (2,2) 1st win
(3,1) 2nd win (3,2) 2nd winfor 4 holes and 3 holes guns
(1,1) 1st win (1,2) 1st win (1,3) 1st win
(2,1) 2nd win (2,2) 1st win (2,3) 1st win
(3,1) 2nd win (3,2) 2nd win (3,3) 1st win
(4,1) 2nd win (4,2) 2nd win (4,3) 2nd win
for 5 holes and 4 holes guns
(1,1) 1st win (1,2) 1st win (1,3) 1st win (1,4) 1st win
(2,1) 2nd win (2,2) 1st win (2,3) 1st win (2,4) 1st win
(3,1) 2nd win (3,2) 2nd win (3,3) 1st win (3,4) 1st win
(4,1) 2nd win (4,2) 2nd win (4,3) 2nd win (4,4) 1st win
(5,1) 2nd win (5,2) 2nd win (5,3) 2nd win (5,4) 2nd win
and so on....if we pay attention at the combinations above, they create pattern of 2 triangle
1st player win at upper triangle and 2nd player win in lower triangle
both triangle are same size, so both player have same chance to win. 
1 2 3 4
5 6 7 8
if I label the options like number 1 to 8 above
I think the answer is number 4
all other shape are duplicates, only number 4 is not a duplicate
Prove that you solved sudoku
in New Logic/Math Puzzles
Posted
after a week long journey abroad, now I'm active again.
After thinking again, and using the clue harrey give us (scisors, pen, and paper),
Yes it is possible to prove it without computer, but it takes many steps.